Originally Posted by
dourvas
while($result = mysql_fetch_array($qry))
hi there,
you get error at this line becuase in mysql_fetch_array($result) function can takes only result variable which holds output generated by $result=mysql_query($qry);
hope you understand.
Now for deleting part ,me also suggest make table which contain each row returned by query and last column contains link which hold link of php processing page and primary key of that row in the form of querysting.
please check this Url
http://www.experts-exchange.com/Web_..._23328726.html
Hope this will help you.
Thanks & Regards
Dilip Kumar Vishwakarma
Last edited by dilipv; Dec 29th, 2008 at 2:46 am.
Dilip Kumar Vishwakarma
Programmer
.Net Consulting
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