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Open variable named files

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Join Date: Jul 2008

Posts: 21

Reputation: azwraith69 is an unknown quantity at this point

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azwraith69 azwraith69 is offline

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Open variable named files

Jan 24th, 2009

hello,,

i need help on how to open files by using variable names..

here's my function:

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void stringSearcher(string filename, string search)
{
	ifstream file;
	file.open(filename);
	if(!file.is_open())
	{
		cerr<<"File can't be open..."<<endl;
		exit(1);
	}
	string line;

	while(!file.eof())
	{
		getline(file, line);
		if(line.find(search)==0)
		{
			displayTitle(line);
			exit(1);
		}
	}
}
void stringSearcher(string filename, string search) { ifstream file; file.open(filename); if(!file.is_open()) { cerr<<"File can't be open..."<<endl; exit(1); } string line; while(!file.eof()) { getline(file, line); if(line.find(search)==0) { displayTitle(line); exit(1); } } }

my problem is that there's always an error on the file.open line...
"no matching function to call...etc"

this is where i call the function in my main:

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while (pent=readdir(pdir))
    {
        if (checkXML(pent->d_name))
        {
             list.push_back(pent->d_name);
	     string title("<TITLE>");
	     stringSearcher(pent->d_name, title);
        }
    }
while (pent=readdir(pdir)) { if (checkXML(pent->d_name)) { list.push_back(pent->d_name); string title("<TITLE>"); stringSearcher(pent->d_name, title); } }

sorry if you don't understand it,,

thx for helps... i need this asap btw,,

Last edited by azwraith69; Jan 24th, 2009 at 10:47 pm.

I am living in a mere program...

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Join Date: Jun 2005

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Rashakil Fol Rashakil Fol is offline

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Re: Open variable named files

Jan 24th, 2009

When you see it say that there's "no matching function", that means there's no function with the given name that expects the types you've provided. If you double-check the documentation for ifstream's open function, you'll see that it takes a char*, not a string.

So use the .c_str() member function to get a char*.

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Join Date: Jul 2008

Posts: 21

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azwraith69 azwraith69 is offline

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Re: Open variable named files

Jan 24th, 2009

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Originally Posted by Rashakil Fol

When you see it say that there's "no matching function", that means there's no function with the given name that expects the types you've provided. If you double-check the documentation for ifstream's open function, you'll see that it takes a char*, not a string.

So use the .c_str() member function to get a char*.

thx,, for quick reply,,

i have just did that..

now,, there's no more errors,,

but the problem is,, File can't be open...

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Help with Code Tags

(Toggle Plain Text)
void stringSearcher(string filename, string search)
{
	ifstream file;
	ifstream openfile(filename.c_str());
	if(!file.is_open())
	{
		cerr<<"File can't be open..."<<endl;
		exit(1);
	}

	string line;
	while(!file.eof())
	{
		getline(file, line);
		if(line.find(search)==0)
		{
			displayTitle(line);
			exit(1);
		}
	}
}
void stringSearcher(string filename, string search) { ifstream file; ifstream openfile(filename.c_str()); if(!file.is_open()) { cerr<<"File can't be open..."<<endl; exit(1); } string line; while(!file.eof()) { getline(file, line); if(line.find(search)==0) { displayTitle(line); exit(1); } } }

when i cout the filename,, it is right,, for example -> "file.xml"
and it is in the same directory with my source codes..
but it can't be open using .c_str()..

if i use file.open("file.xml"),, it opens properly....

what's the problem??

thx again,,

I am living in a mere program...