DaniWeb Forum Index > Software Development > C++

Overloading Of ( ) is possible

Please support our C++ advertiser: Intel Parallel Studio Home

Thread Solved

•

Join Date: Jan 2009

Posts: 25

Reputation: nitu_thakkar has a little shameless behaviour in the past

Solved Threads: 1

nitu_thakkar nitu_thakkar is offline

Offline

Light Poster

Overloading Of ( ) is possible

Feb 20th, 2009

hello everone

i'm new to c++ language

Is This possible to make prg in cpp to overload () Opratore

if yes, then can u pls give any logical flow for develope the prg

i.e. which kind of opeartion can be performed through () opratore

thanx in advance

•

Join Date: Jul 2005

Posts: 1,758

Reputation: Lerner is a name known to all

Solved Threads: 283

Lerner

Offline

Posting Virtuoso

Re: Overloading Of ( ) is possible

Feb 20th, 2009

Are you thinking about using the () as the conversion operator or talking about overloading the () operator to do something like addition or concatenation or some other theoretical possibility?

Last edited by Lerner; Feb 20th, 2009 at 3:43 pm.

Klatu Barada Nikto

•

Join Date: Jan 2009

Posts: 25

Reputation: nitu_thakkar has a little shameless behaviour in the past

Solved Threads: 1

nitu_thakkar nitu_thakkar is offline

Offline

Light Poster

Re: Overloading Of ( ) is possible

Feb 20th, 2009

hi......

i have some idea that in overloading of + operatore we can

perform summation or can concate to string

so whould u pls tell me which kind of

operation should i perform for overload the

() as operatore

•

Join Date: Sep 2004

Posts: 7,856

Reputation: Narue has a reputation beyond repute

Solved Threads: 755

Narue

Offline

Senior Bitch

Re: Overloading Of ( ) is possible

Feb 20th, 2009

When you overload the () operator, it's used as if it were a function call operator and nothing more:

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
#include <iostream>
 
struct foo {
    void operator()()
    {
        std::cout<<"FOO!\n";
    }
};
 
int main()
{
    foo bar;
 
    bar();
}
#include <iostream>

struct foo {
    void operator()()
    {
        std::cout<<"FOO!\n";
    }
};

int main()
{
    foo bar;

    bar();
}

If that's not what you want, you're SOL.