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Loop was vectorized
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I don't know how to solve this problem in my code
voro.cpp(200): (col. 5) remark: LOOP WAS VECTORIZED
voro.cpp(395): same problem
voro.cpp(423):
voro.cpp(427):
I am using intel compiler 10.1 to compile my code
the code works fine on dev C++ 4.9.9.2 and V C++ 2008
200
395
423
427
Thank you for your time
voro.cpp(200): (col. 5) remark: LOOP WAS VECTORIZED
voro.cpp(395): same problem
voro.cpp(423):
voro.cpp(427):
I am using intel compiler 10.1 to compile my code
the code works fine on dev C++ 4.9.9.2 and V C++ 2008
200
C++ Syntax (Toggle Plain Text)
395
C++ Syntax (Toggle Plain Text)
423
C++ Syntax (Toggle Plain Text)
427
C++ Syntax (Toggle Plain Text)
Thank you for your time
It's only a hint that the compiler generated code which can be executed parallely, IIRC.
If you are forced to reinvent the wheel at least try to invent a better one!
Please use code tags - Please mark solved threads as solved
Please use code tags - Please mark solved threads as solved
sorry my c++ knowledge is self taught
thank you
when i run the code it will randomly crash with
segmentation fault (i thought this was linked to the compiler remark)
thank you
when i run the code it will randomly crash with
segmentation fault (i thought this was linked to the compiler remark)
Last edited by nahmartin; Jun 26th, 2009 at 8:19 am.
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Practically a Posting Shark
When one vectorized their code the idea is to have the three or four components processed side by side.
Re-examine your loops as you have a problem. They're all exclusive but some are {0...2} and some are {0...3} for XYZ and XYZW processing. Was that intentional?
You haven't shown your declarations so difficult to tell if you're out of range thus causing your segmentation fault.
Also you only show snippets but do a pre-divide by zero check! Typically in vectors you're just not dividing a vector by a scalar. You are generating a product by multiplying a vector by a reciprocal scalar. If that is the case, if the divisor (typically a magnitude) is very close to zero, then don't do the 'division'. As the divident approaches zero, the result of the reciprocal-square root is negligible thus use the algebraic multiplicative identity (N = N * 1) thus N = N.
Re-examine your loops as you have a problem. They're all exclusive but some are {0...2} and some are {0...3} for XYZ and XYZW processing. Was that intentional?
You haven't shown your declarations so difficult to tell if you're out of range thus causing your segmentation fault.
Also you only show snippets but do a pre-divide by zero check! Typically in vectors you're just not dividing a vector by a scalar. You are generating a product by multiplying a vector by a reciprocal scalar. If that is the case, if the divisor (typically a magnitude) is very close to zero, then don't do the 'division'. As the divident approaches zero, the result of the reciprocal-square root is negligible thus use the algebraic multiplicative identity (N = N * 1) thus N = N.
thank you wildgoose
the loops were intentional one is position the other rotation (quaternions)
I have checked for for
pointing to un-initialised variables
and
pointing to outside of allocated vectors and matrices
what else would cause a segmentation fault
i do have this
would either cause a segmentation error (Unfortunately i get this error at university using the icc 10.1 compiler so i cannot check myself)
the loops were intentional one is position the other rotation (quaternions)
I have checked for for
pointing to un-initialised variables
and
pointing to outside of allocated vectors and matrices
what else would cause a segmentation fault
i do have this
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string style;
char* output_file;
style = argv[1];
output_file = argv[14];
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Join Date: Jun 2009
Posts: 830
Reputation:
Solved Threads: 94
Practically a Posting Shark
argv[] You really have 14 command line arguments? [0] is path.
In your matrics [][] you show i as an index but you don't show what it is set to! I'm assuming it contains a valid index?
Other then that I don't spot an indexing error. Provided your vectors are [4] and [4][4].
This is a good time to also make sure your vector's and matrices are properly aligned. The first step is Pseudo Vector code such as you're doing now. The next logical step is using SIMD (Single-Instruction Multiple Data) operands (Assembly Language).
In your matrics [][] you show i as an index but you don't show what it is set to! I'm assuming it contains a valid index?
Other then that I don't spot an indexing error. Provided your vectors are [4] and [4][4].
This is a good time to also make sure your vector's and matrices are properly aligned. The first step is Pseudo Vector code such as you're doing now. The next logical step is using SIMD (Single-Instruction Multiple Data) operands (Assembly Language).
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