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half diamond output in java
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hi im having problem on how to make the output of my programme like this:
if you enter a number: (EVEN)
*
**
***
*****
If you enter a number
ODD)
*****
****
***
**
*
im always having an output of:
(EVEN)
*
**
***
****
(ODD)
*****
****
***
**
*
I hope somebody will haelp me:
here is my code:
import java.io.*;
public class del
{
public static void main(String[]args)throws IOException
{
BufferedReader IN = new BufferedReader(new InputStreamReader(System.in));
int a, c, d;
String b, e, f;
do{
System.out.println("Enter name:");
f = IN.readLine();
System.out.println("Enter a number:");
b = IN.readLine();
d = Integer.parseInt(b);
if(d%2==0)
{
for(a=d;a>=0;a--)
{
for(c=a;c<d;c++)
{
System.out.print(f);
}
System.out.println(" ");
}
}
else
{
for(a=0;a<=d;a+=1)
{
for(c=a;c<d;c++)
{
System.out.print(f);
}
System.out.println(" ");
}
}
System.out.print("Try Again?:");
e = IN.readLine();
}while(e.charAt(0)=='y'||e.charAt(0)=='Y');
}
}
if you enter a number: (EVEN)
*
**
***
*****
If you enter a number
ODD)*****
****
***
**
*
im always having an output of:
(EVEN)
*
**
***
****
(ODD)
*****
****
***
**
*
I hope somebody will haelp me:
here is my code:
import java.io.*;
public class del
{
public static void main(String[]args)throws IOException
{
BufferedReader IN = new BufferedReader(new InputStreamReader(System.in));
int a, c, d;
String b, e, f;
do{
System.out.println("Enter name:");
f = IN.readLine();
System.out.println("Enter a number:");
b = IN.readLine();
d = Integer.parseInt(b);
if(d%2==0)
{
for(a=d;a>=0;a--)
{
for(c=a;c<d;c++)
{
System.out.print(f);
}
System.out.println(" ");
}
}
else
{
for(a=0;a<=d;a+=1)
{
for(c=a;c<d;c++)
{
System.out.print(f);
}
System.out.println(" ");
}
}
System.out.print("Try Again?:");
e = IN.readLine();
}while(e.charAt(0)=='y'||e.charAt(0)=='Y');
}
}
•
•
Join Date: Oct 2008
Posts: 2,612
Reputation: 
Solved Threads: 464
Welcome sympatiko.
Use BB code tags. Your source code must be surrounded with bb code tags. Read How to wrap up source code with bb code tags?
You are near to the solution. Keep it up.
Use BB code tags. Your source code must be surrounded with bb code tags. Read How to wrap up source code with bb code tags?
You are near to the solution. Keep it up.
Failure is not fatal, but failure to change might be. - John Wooden
•
•
•
•
Originally Posted by adatapost 
Welcome sympatiko.
Use BB code tags. Your source code must be surrounded with bb code tags. Read How to wrap up source code with bb code tags?
You are near to the solution. Keep it up.
•
•
Join Date: Oct 2008
Posts: 2,612
Reputation:
Solved Threads: 464
Input a number and if it is odd then make it even.
Failure is not fatal, but failure to change might be. - John Wooden
•
•
Join Date: Jan 2008
Posts: 3,813
Reputation:
Solved Threads: 501
•
•
•
•
Originally Posted by sympatiko
im a newbie in programming,,i cant understand those kind of coding,,can you please solve my problem if you know?
[code]
// paste code or pattern here
[/code]
Note the difference (with code tags):
Java Syntax (Toggle Plain Text)
Without code tags:
*
*
*
*
Please repost using code tags, as explained above. Again, do this to retain spacing. Thanks.
[code]
// paste code or pattern here
[/code]
•
•
•
•
Originally Posted by sympatiko
hi im having problem on how to make the output of my programme like this:
if you enter a number: (EVEN)
*
**
***
*****
If you enter a number
*****
****
***
**
*
im always having an output of:
(EVEN)
*
**
***
****
(ODD)
*****
****
***
**
*
I hope somebody will haelp me:
here is my code:
import java.io.*;
public class del
{
public static void main(String[]args)throws IOException
{
BufferedReader IN = new BufferedReader(new InputStreamReader(System.in));
int a, c, d;
String b, e, f;
do{
System.out.println("Enter name:");
f = IN.readLine();
System.out.println("Enter a number:");
b = IN.readLine();
d = Integer.parseInt(b);
if(d%2==0)
{
for(a=d;a>=0;a--)
{
for(c=a;c<d;c++)
{
System.out.print(f);
}
System.out.println(" ");
}
}
else
{
for(a=0;a<=d;a+=1)
{
for(c=a;c<d;c++)
{
System.out.print(f);
}
System.out.println(" ");
}
}
System.out.print("Try Again?:");
e = IN.readLine();
}while(e.charAt(0)=='y'||e.charAt(0)=='Y');
}
}
if even:
*
****
******
if odd:
******
****
*
so now,,give me the code,,how to make that
•
•
•
•
Originally Posted by sympatiko
i mean the real output put must be
if even:
*
****
******
if odd:
******
****
*
so now,,give me the code,,how to make that
•
•
Join Date: Oct 2008
Posts: 2,612
Reputation:
Solved Threads: 464
Use bb code tag. Read this - How to use code tag?
Failure is not fatal, but failure to change might be. - John Wooden
•
•
Join Date: Oct 2008
Posts: 2,612
Reputation:
Solved Threads: 464
Java Syntax (Toggle Plain Text)
Failure is not fatal, but failure to change might be. - John Wooden
|
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