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indentation error

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johndoe444 johndoe444 is offline Offline
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indentation error

 
0
  #1
Jul 1st, 2009
Hi,
This is the existing code:

Python Syntax (Toggle Plain Text) 
  1. for c in chartNames:            
  2. 		chartUrl = baseChartUrl+c
  3. 		hd = extractChart(chartUrl)
  4.  
  5. 		writeChart(hd,c)		
  6.  
  7. 		for key in hd:			
  8. 			if key in chart:
  9. 				chart[key].append(c)
  10. 			else:
  11. 				chart[key] = [c]

when i wanted to insert a line before

Python Syntax (Toggle Plain Text) 
  1. chartUrl = baseChartUrl+c

by putting the cursor to the end of the

Python Syntax (Toggle Plain Text) 
  1. for c in chartNames:

and pressing an enter I get compile error.

what's happening here?
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rupeshpradhan rupeshpradhan is offline Offline
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Re: indentation error

 
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  #2
Jul 1st, 2009
1. Can you please make the indentation level to 4 spaces.

2. Please use 'code=python' surrounded by square '[ ]' bracets so that it will be correctly cololur coded and end with '\code' enclosed in the same square brackets. Click on the link below for mode details on code tags
http://www.daniweb.com/forums/misc-e...=400&width=680

OR you can click the link on the right side in the box below called '
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This is what your code should look like:
python Syntax (Toggle Plain Text) 
  1. for c in chartNames:
  2.     chartUrl = baseChartUrl+c
  3.     hd = extractChart(chartUrl)
  4.  
  5.     writeChart(hd,c)
  6.  
  7.     for key in hd:
  8.         if key in chart:
  9.             chart[key].append(c)
  10.         else:
  11.             chart[key] = [c]

3. Please provide hard coded values and to the list / tuple / dictionary & variables and function so that it is executable and gives an output or atleast a traceback
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evstevemd evstevemd is offline Offline
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Re: indentation error

 
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  #3
Jul 1st, 2009
what editor do you use?
Get ulipad
http://code.google.com/p/ulipad/
Atheist: God is man made imagination, he doesn't exist!
Theist: It's okay, can you imagine anything else that doesn't exist?
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Re: indentation error

 
0
  #4
Jul 1st, 2009
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by putting the cursor to the end of the
for c in chartNames:
and pressing an enter I get compile error.
"I get a compile error" is too vague for anyone to figure out. It is probably that the blank line is not indented at the same level as the other lines and your editor does not like that (which is overly picky, but at the discretion of whoever wrote the editor), but as I said it is impossible to decipher without the line number of the error and what it is. Use try/except, especially when testing.
Python Syntax (Toggle Plain Text) 
  1. try:
  2.     for c in chartNames:
  3.         chartUrl = baseChartUrl+c
  4.         hd = extractChart(chartUrl)
  5.  
  6.         writeChart(hd,c)
  7.  
  8.         for key in hd:
  9.             if key in chart:
  10.                 chart[key].append(c)
  11.             else:
  12.                 chart[key] = [c]
  13. except:
  14.     import traceback
  15.     traceback.print_exc()
  16.     raise
Last edited by woooee; Jul 1st, 2009 at 2:09 pm.
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Re: indentation error

 
0
  #5
Jul 1st, 2009
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Originally Posted by evstevemd View Post
what editor do you use?
Get ulipad
http://code.google.com/p/ulipad/
How long have you known about this?
And why haven't you told us until now?!
1. Use Code Tags.
2. Homework? Show Effort.
3. Keep discussions on the forum: no PMs
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