create an empty list L
for each character c in word:
    find the ideogram x corresponding to c
    append x to our list L
# now the problem is to display the result
# we display the 5 lines one after the other
for each i in 1, 2, 3, 4, 5:
    initialize the i-th line S to the empty string
    for each ideogram x in L:
        find the i-th line y of x # for example 2nd line of the first ideogram is 0 X 0 X
        concatenate y to S
    print S

base_dict = {}
base_dict["A"] = """X 0 X X
0 X 0 X
0 0 0 X
0 X 0 X
0 X 0 X"""
 
base_dict["B"] = """0 0 X X
0 X 0 X
0 0 X X
0 X 0 X
0 0 X X"""
 
base_dict["C"] = """X 0 X X
0 X 0 X
0 X X X
0 X 0 X
X 0 X X
"""
 
for key in ("A", "B", "C"):
   print key, "-" *60
   print base_dict[key]

base = "ABC"
 
FIVEHIGH = (
"""
X 0 X X
0 X 0 X
0 0 0 X
0 X 0 X
0 X 0 X 
""",
"""
0 0 X X
0 X 0 X
0 0 X X
0 X 0 X
0 0 X X
""",
"""
X 0 X X
0 X 0 X
0 X X X
0 X 0 X
X 0 X X
""")
 
class Ideogram(tuple):
    def __new__(cls, string):
        return tuple.__new__(cls, (y for y in (x.strip() for x in string.split("\n")) if y))
    def __init__(self, *args):
        assert(len(self) == 5)
 
 
base_dict = dict(zip(tuple(base), (Ideogram(x) for x in FIVEHIGH)))
 
def translate(word):
  lines = list(list() for i in range(5))
  for letter in (c for c in word.upper() if c in base_dict): # skip characters that dont belong to base
     for i, x in enumerate(base_dict[letter]):
        lines[i].append(x)
  return "\n".join(" ".join(L) for L in lines)
 
if __name__ == "__main__":
    word = raw_input("Enter word:")
    print translate(word)

def join_letters( letter_list, base_dict ):
   combined_rows_dict = {}
 
   ##---  base length to test for equality
   len_letter = len(base_dict[letter_list[0]])
 
   for j in range(0, len(letter_list)):
      this_letter = letter_list[j]
 
      ##--- all letters must be in the dictionary
      if this_letter not in base_dict:
         print "letter %s not in base_dict" % (this_letter)
         return "***"
 
      ##--- test for all translations are equal in length
      if len(base_dict[this_letter]) != len_letter:
         print "unequal letter lengths", len_letter, len(base_dict[this_letter])
         return "***"
 
      ##--- convert triple quote string into rows in a list
      string_list = base_dict[this_letter].split("\n")
      print "string_list", string_list
 
      ##---  append each row to the corresponding dictionary key
      for row in range(0, len(string_list)):
         if row not in combined_rows_dict:
            combined_rows_dict[row] = []
         combined_rows_dict[row].append(string_list[row])
 
   print
   for row in range(0, len(combined_rows_dict)):
      this_row = combined_rows_dict[row]
      print " ".join(this_row)
   return "Success"
 
base_dict = {}
base_dict["A"] = """X 0 X X
0 X 0 X
0 0 0 X
0 X 0 X
0 X 0 X"""
 
base_dict["B"] = """0 0 X X
0 X 0 X
0 0 X X
0 X 0 X
0 0 X X"""
 
base_dict["C"] = """X 0 X X
0 X 0 X
0 X X X
0 X 0 X
X 0 X X"""
 
##for key in ("A", "B", "C"):
##   print key, "-" *60
##   print base_dict[key]
 
print join_letters(["A", "C", "B"], base_dict)