Hi,
I'm a beginner of C++ programming. I am trying to write a void funtion for the following question but in vain. Please help me.
Here's the question:
Suppose we want to display the following figure containing the alphabetic character V on yhe screen:
#^^^^^^^^^#
^#^^^^^^^#^
^^#^^^^^#^^
^^^#^^^#^^^
^^^^#^#^^^^
^^^^^#^^^^^
We want to be able to change the number of rows. In the figure above the number of rows is 6. If the number of rows is 4. the figure will look as follows:
#^^^^^#
^#^^^#^
^^#^#^^
^^^#^^^
Write a void function drawShape that displays such a figure on the screen. There should be one parameter (of type int), namely the number of rows as indicated above.
The hint i have here is:
Use for loops. Suppose nrP contains the number of rows. Then the ith row should consist of (i - 1)^ characters, followed by one #character, followed by (2 * nrP - 2 * i - 1)^ characters, followed by another # character, followed by another (i - 1)^ characters. The last row however, should contain only one # character.

Here's what i have written till now:
void drawShape (int nrP)
{
for (int i = 1); i <= n; i++)
cout << '#' << '^' << endl;
}
But the above does not work of course.

You'll need 2 for loops (nested). 1 will be for the width and one for the height.


Inside the second for loop (rows) you'll have to implement the formulas they gave you in the book/assignment. Use something like if statements to calculate whether it should print a ^ or a #.

It would probably be easier to generate a small 'V' by hand and figure out what coordinates that the '#' lands on. Then you can decipher the pattern and come up with what you would need to be put inside the for loops. Sometimes it's easier to do things by hand just so you can visualize it.

the answer is in the hint. I'll add that you need to use the hint for five loops, and for the last line use a separate set of three loops. The answer is right there. look at it again. It is not as hard as you think, I promise.
Each character in the line should have its own loop.

my earlier post was able to print the required shape but '^' was replaced by space.
(row provided should fit to screen, otherwise side effects).

The code below again shows that same thing can be done in one for loop, giving an idea how c++ is rich in features.
If last line setw(i-1) is repalced by setw(i), the output will be in more or less square shape, otherwise as ask in post.

yeah, you could do it that way but it is highly inefficient. there is one way that you can do this using 2 for loops and a simple if/else statement. however codeguru_2009 has an even more efficient solution than mine.

I've been able to write the following program but there is still some problem. Can you help please?
#include <iostream>
using namespace std;

void drawShape(int nrP)
{
for (int i = 1; i <= nrP; i++)
{
s1 = i - 1;
s2 = (2 * nrP - 2 * i - 1);
for (int j = 1; j <= s1; j++)
cout << '^';
cout << '#';
for (int j = 1; j <= s2; j++)
cout << '^';
cout << '#';
for (int j = 1; j <= s1; j++)
cout << '^';
cout << endl;
}
}

int main()
{
int nr;

cout << "Number of rows: ";
cin >> nr;
drawShape(nr);

return 0;
}

Here is your code indented with code tags.

One problem with your function is that you never declared s1 and s2.

Below code fixes that :

Thank you very much firstPerson but there's still a little problem. In the last row two '#' is being displayed instead of one. And i am not being able to figure out the problem.