Split string into char array
 

Hi, I was wonder if someone could give me some help with my program

I have a variable:

char *insert = "abcdefgh"

and i want to split that into chars like so, 'a', 'b', 'c', 'd', etc.

I've tried ToCharArray(), but that doesnt seem to work

Re: Split string into char array
 

>I have a variable:
>char *insert = "abcdefgh"
>and i want to split that into chars like so, 'a', 'b', 'c', 'd', etc.
Uh, you're done. A string literal is an array of const char and except for modification, sizeof, and address-of you can use the pointer as if it were an array. If you need an actual array, you can do this:

char insert[] = "abcdefgh";

C doesn't have a special string type like Java, so when you're using a string in C, you're really using an array.

Re: Split string into char array
 

a string in c/c++ is a array of characters so extract then like so

#include <iostream>

int main(int argc, char**argv)
{
char *insert = "abcdefg";


for (int i = 0; i < 7; ++i)
std::cout<<insert[i]<<"\n";

}

Re: Split string into char array
 

This is C forum. Not C/C++ ;)
Take the time to read how properly tag your code so instead of looking like this:
#include <iostream>

int main(int argc, char**argv)
{
char *insert = "abcdefg";


for (int i = 0; i < 7; ++i)
std::cout<<insert[i]<<"\n";

}

It would look like this:

#include <iostream>



int main(int argc, char**argv)

{

    char *insert = "abcdefg";





    for (int i = 0; i < 7; ++i)

    std::cout<<insert[i]<<"\n";



}

For how to do that read here and here
I don't promise that it'll fix your code, but it'll make it more readable.

hmm try this
but i'm not sure i'm just a first yr student

char a
char b
.
.
.
char g

hee hee

we're not finished discussing array yet

hmm

>but i'm not sure i'm just a first yr student
If you're not sure, don't answer because you're more likely to lead people astray with bad advice than do any good.

>hee hee
Oh, I get it. You're joking. Because anybody who would jump into a thread over a year after it unofficially ended and offer something as inane as your "help" is either trying to get a laugh or is a complete retard. I don't think you're a complete retard (yet), so it must be a pitiful attempt at humor. :icon_rolleyes:

If you really want to make an array of char without '\0' at the end of it. You could make something like this

#include<stdio.h>



int main()

{

char *insert = "abcdefgh";

char outsert[8]; //I use 8 because abcdefgh contains 8 char

int i;



for (i=0;i<8;i++)

{

outsert[i] = insert[i];

}



return 0;

}

But i can't imagine what you only can do with array of char. Please answer me.

char *insert = "abcdefgh";

char outsert[8]; //I use 8 because abcdefgh contains 8 char
int i;
for (i=0;i<8;i++)
{
outsert[i] = insert[i];
}
in array outsert you will found array of character .......