Do/While Loop help
 

Thanks for the help earlier, I fixed the problem i had earlier in nested loops, but now i need help creating a Do/While Loop that is a loop above all the steps above that ask the user to continue y or n and quit unless they enter y. i know how to terminate the program.


#include <iostream>
using namespace std;

int main()
{
int number, dig1, dig2, dig3;
char answer;
cout << "Enter a Positive Integer from 0 to 999." << endl;
cin >> number;
while ((number < 0) || (number > 999))
{
cout << "Error: Negative Number or Number Greater than 999\n" << "Reenter that number and continue: \n";
cin >> number; }

dig1 = number / 100;
dig2 = (number % 100 - number % 10) / 10;
dig3 = number % 10;

for ( int i = 0; i <= dig1; i++ ) {
for ( int j = 0; j <= ( ( i == dig1 ) ? dig2 : 9 ); j++ ) {
for ( int k = 0; k <= ( ( j == dig2 ) ? dig3 : 9 ); k++ )
cout<< i << j << k <<endl;
}
}

do{
cout << "Do you want to continue (y/n)?\n";
cin >> answer;
} while (answer != 'n'
cout << "goodbye!\n";



return 0;


}

Re: Do/While Loop help
 

The entire program should be nested in your do..while loop:

int main()

{

  int number, dig1, dig2, dig3;

  char answer;



  do {

    // Everything else in here

  } while ( answer != 'n' );

}

And you should consider allowing 'N' as well as 'n' to be more user friendly.

Re: Do/While Loop help
 

I tried your solution already but when the user types 'n' the program runs once more and outputs goodbye before terminating.

Re: Do/While Loop help
 

I don't have any problems with it:

#include <iostream>

using namespace std;



int main()

{

  int number, dig1, dig2, dig3;

  char answer;



  do {

    cout << "Enter a Positive Integer from 0 to 999." << endl;

    cin >> number;

    while ((number < 0) || (number > 999))

    {

      cout << "Error: Negative Number or Number Greater than 999\n" << "Reenter that number and continue: \n";

      cin >> number;

    }



    dig1 = number / 100;

    dig2 = (number % 100 - number % 10) / 10;

    dig3 = number % 10;



    for ( int i = 0; i <= dig1; i++ ) {

      for ( int j = 0; j <= ( ( i == dig1 ) ? dig2 : 9 ); j++ ) {

        for ( int k = 0; k <= ( ( j == dig2 ) ? dig3 : 9 ); k++ )

          cout<< i << j << k <<endl;

      }

    }



    cout << "Do you want to continue (y/n)?\n";

    while ( cin.get ( answer ) && answer != '\n' )

      ;

    cin >> answer;

  } while (answer != 'n');



  cout << "goodbye!\n";



  return 0;

}

I even added a paranoia check to flush the input stream because that sounds like the problem you're having.

Re: Do/While Loop help
 

do{
//prog. body here
} while (answer != 'n')
cout << "goodbye!\n";

Re: Do/While Loop help
 

You're about six days too late, slick. If you're going to take that long to post a reply to a question that was already answered then at least add something entertaining to the thread.

To Get the Factorial Of any Number
 

#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
int n, i, fac;
fac=1;
i=1;
do
{
fac*=n;
i++;
}
while(i<=n);
cout<<"\n\n Answer --> "<<fac;
getch();
}


//OUTPUT --> This will get the factorial of any number