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| i'm a rookie, please help with MIPS so i'm learning MIPS right now and i think i get the hang of things, mind you it's all relatively easy (so i've been told), but i can't seem to get around this one problem. i was given a C++ fragment and need to convert (translate) it directly to MIPS. and that equation is array[a+b] = array[a-b]+d intially i thought, this would be the same as array[a]+array[b] = array[a+b]...and of course i was wrong. though wrong, i'd still like to post what i do have....and if someone can correct me and guide me to the right direction, that'll be great! add $t1, $s0, $s0 # $t1 = 2*athanks in advance to the admin: see i have put a HONEST effort...so can i now get help? /lol |
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