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| XSL related question Hi I wasn't sure as to where I need to post XSL related questions..Is there anyone in this group who has expertise with XSL? If anyone can help me out with an XSL related question, that would be great. Ani |
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| Re: XSL related question |
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| Re: XSL related question In the code below I am just writing a simple for loop in XSL...Instead of creating a dynamic variable name, I have created a variable called sublink1 and later give a dynamic value to it based on loop variable's current value...Later construct a link with "sublink1"..Concept works fine without the for-each..I mean it generated only one link rather than 2 links...But when i give for-each, it doesn't display either of the links... XML file: <item> <count>one</count> <sub>2</sub> /*this tells the XSL file as to how many sublinks are listed..I have used that for running the for loop*/ <sublink1>http://www.yahoo.com</sublink1> <subtitle1>Yahoo</subtitle1> <sublink2>http:www.google.com</sublink2> <subtitle2>Google</subtitile2> </item> XSL file: <div id="sublinklist" align="left" class="anylinkcss" style="width: 70.5px; background-color: black"> <xsl:for-each select="$sub"> <xsl:variable name="sublink1"> <xsl:value-of select="concat('sublink',$sub)"/> </xsl:variable> <xsl:variable name="subtitle1" select="subtitle1"/> <a href="{sublink1}"> <xsl:value-of select="subtitle1"/> </a> </xsl:for-each> </div> Any suggestions? Ani Quote:
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