converting bool[8] to char
 

hey..I need to convert a 8 value bool array to char.How can I do this?

Re: converting bool[8] to char
 

You can use the bool array as a "bit-position" array for the representation of a char.

#include <iostream>



using std::cout;

using std::cin;

using std::endl;



int main(){

     bool bits[] = {0, 1, 0, 0, 0, 0, 0, 1};

     char c = 0;

     for(int i = 0; i < 8; i++)

           c += (bits[i] >> i); // 0 or 1 times 2 to the ith power

     cout << c << endl; // should print out A

     cin.get();

     return 0;

}

Edit: I'm not near a compiler, so the bit-shifting operator may need to be switched but the logic is straightfoward.

Hopefully this helps! =)

-Alex

Re: converting bool[8] to char
 

I had

char boolsToChar(bool* bools){

     char c = 0;

     for( int i = 0; i < 8; i++ )

          if( bools[i] ) 

              c += pow(2,i);

     return c;

}

but clearly this is not as nice a solution as above, For multiple reasons.

One being that I get a warning for converting a double to a char and two I have a conditional statment that i clearly don't require

Anyhow the solution above compiled for me, but I needed to change it around a little to come up with 'A'.

    bool bits[] = {1, 0, 0, 0, 0, 0, 1, 0};

    char c = 0;

    for(int i = 0; i < 8; i++)

           c += (bits[i] << i); // 0 or 1 times 2 to the ith power

    cout << c << endl; // should print out A

    cin.get();

Re: converting bool[8] to char
 

Hmm, try changing char to unsigned (if it exists @_@ )

-Alex

Edit: I am really tired #_#

I didn't realize I made the array back-asswards XD

XP

Re: converting bool[8] to char
 

How about this, rather unusual method ;)

#include <iostream>



struct octet {

  union {

    char val;

    struct {

      unsigned h : 1;

      unsigned g : 1;

      unsigned f : 1;

      unsigned e : 1;

      unsigned d : 1;

      unsigned c : 1;

      unsigned b : 1;

      unsigned a : 1;

    };

  };

};



int main() {

  bool bits[] = {0, 1, 1, 0, 0, 0, 0, 1};



  octet o;

  o.a = bits[0];

  o.b = bits[1];

  o.c = bits[2];

  o.d = bits[3];

  o.e = bits[4];

  o.f = bits[5];

  o.g = bits[6];

  o.h = bits[7];



  std::cout << o.val; // 01100001 = 'a'

  std::cin.ignore();

}

Theres practically no maths involved :)

Re: converting bool[8] to char
 

Thanks a lot! :D