counting pixels in an image(ocr)
 

I have a small image with a black background and red lines in it and I need to count the red pixels. I know I need PIL, but I'm not sure which method to use. Then once I have the counts I need to equate them to a character, so if the red lines in the image form a circle and have x amount of red pixels, its = '0', and if the image forms a straight line and is found to have x amount of pixels it's = 'l'.

import Image

#mypic.jpg is the circle

im=image.open("mypic.jpg")

im.getcolors(R)

# if statement here

Any suggestions?

Re: counting pixels in an image(ocr)
 

Could you test how many pixels are red? Because a circle will require many more pixels to draw then a line.
I know when getting colours i used something like:

import Image

im = image.open("myPic.jpg")

for pixel in im.getdata():

    #check if it is red

Re: counting pixels in an image(ocr)
 

Played around with it a little ...

# use PIL to count pixels in letters I and O

# image file needs to be a bitmap file to maintain

# red (255,0,0) and black (0,0,0) pixel colors correctly



from PIL import Image



# img_I.bmp --> 50x50 black bg + red I (times new roman, bold, 24)

img_I = Image.open("img_I.bmp").getdata()



# img_O.bmp --> 50x50 black bg + red O (times new roman, bold, 24)

img_O = Image.open("img_O.bmp").getdata()



# count red pixels of the I

# list(img_I) is a list of (r,g,b) color tuples for each pixel

# where (255,0,0) would be the red pixel

red_I = 0

for red in list(img_I):

    if red == (255,0,0):

        red_I += 1



print red_I  # 76



# count red pixels of the O

red_O = 0

for red in list(img_O):

    if red == (255,0,0):

        red_O += 1



print red_O  # 126