Need help changing the address of an array
 

Hi,

I am trying to change the address in an array using *nums++. When I run the program, however, the first number in the array is skipped. What am I missing? How do I get the first number to display?

#include <stdio.h>

int print(int[]);





int main()

{

        #define NUMBERS 7

        int nums[] = {2, 4, 5, 7, 9, 11, 13};



        print(nums);



        return 0;

}



int print (int *nums)

{

        int i;

        i = *nums++;



        for (i = 1; i < NUMBERS; i++, nums++)

        printf("Address %d contains number %d\n", i, *nums );



return 0;



}

Re: Need help changing the address of an array
 

> i = *nums++;
Well this does nothing, except to skip the first entry of the array.
You lose i in the following assignment in the for loop.

Re: Need help changing the address of an array
 

>What am I missing? How do I get the first number to display?

Move

#define NUMBERS 7

outside of main so the function print can see it.
In print() remove

i= *nums++

which is doing harm and producing nothing since you change the value of i inside the loop to start at 1 anyway.

Re: Need help changing the address of an array
 

Not to be picky, but

#define NUMBERS

is a pre-processor directive and doesn't get scope.

(But it should have been outside the function anyway.)

Re: Need help changing the address of an array
 

I tried this and now I have the opposite problem. The last number doesn't print. Suggestions?

Re: Need help changing the address of an array
 

>I tried this and now I have the opposite problem. The last number doesn't print. Suggestions?

start i in the loop at 0 or stop it when is < or equal to NUMBERS

Re: Need help changing the address of an array
 

Thanks! < or equal did just what I wanted.

Re: Need help changing the address of an array
 

see what i have made changes in u r program




#include <stdio.h>
int print(int[]);


int main()
{
#define NUMBERS 7
int nums[] = {2, 4, 5, 7, 9, 11, 13};

print(nums);

return 0;
}

int print (int *nums)
{
int i;
i = (*nums)++;

for (i = 1; i <= NUMBERS; i++, nums++)
printf("Address %d contains number %d\n", i, *nums );

return 0;

}

Re: Need help changing the address of an array
 

somnathsarode if you are going to post code, especially in response to a thread, please use the appropriate code tags.

For this forum:
[code=c]
/* your code goes here */
[/code]

Your response followed the original poster saying "Thanks ... did just what I wanted." Almost seems like the thread was answered doesn't it.

Re: Need help changing the address of an array
 

Well, since I am the original poster, I can say that my question was answered. I was just about to ask if there was a way to mark this as solved when I looked up and saw it right above this box. Sorry I didn't mark it previously. I'm new hear and still learning how the forum works. :-)