| willeffects | Mar 31st, 2005 3:01 am | |
| What do you use to parse the url?
I wouldn't even consider myself a rookie with javascript but know it can be done, so thanks for any help.
What function would I use to have javascript read the page it is on, grab the url which is like:
http://site.com/boards/index.php?sho...37&mode=linear
and say if the url includes "mode=linear" then apply this style sheet?
Thanks!
Will |
| Comatose | Mar 31st, 2005 10:06 am | |
| Re: What do you use to parse the url?
I suppose you could do a
somevariable = window.location;
and then do a substr or substring on the url, and see if it's in there. There might be an easier way, but that's probably how I'd do it. |
| Stan Vitvitskiy | May 17th, 2007 10:22 am | |
| Re: What do you use to parse the url?
Well, try this function, it should be working.
function parseURL(buffer) {
var result = { };
result.protocol = "";
result.user = "";
result.password = "";
result.host = "";
result.port = "";
result.path = "";
result.query = "";
var section = "PROTOCOL";
var start = 0;
var wasSlash = false;
while(start < buffer.length) {
if(section == "PROTOCOL") {
if(buffer.charAt(start) == ':') {
section = "AFTER_PROTOCOL";
start++;
} else if(buffer.charAt(start) == '/' && result.protocol.length() == 0) {
section = PATH;
} else {
result.protocol += buffer.charAt(start++);
}
} else if(section == "AFTER_PROTOCOL") {
if(buffer.charAt(start) == '/') {
if(!wasSlash) {
wasSlash = true;
} else {
wasSlash = false;
section = "USER";
}
start ++;
} else {
throw new ParseException("Protocol shell be separated with 2 slashes");
}
} else if(section == "USER") {
if(buffer.charAt(start) == '/') {
result.host = result.user;
result.user = "";
section = "PATH";
} else if(buffer.charAt(start) == '?') {
result.host = result.user;
result.user = "";
section = "QUERY";
start++;
} else if(buffer.charAt(start) == ':') {
section = "PASSWORD";
start++;
} else if(buffer.charAt(start) == '@') {
section = "HOST";
start++;
} else {
result.user += buffer.charAt(start++);
}
} else if(section == "PASSWORD") {
if(buffer.charAt(start) == '/') {
result.host = result.user;
result.port = result.password;
result.user = "";
result.password = "";
section = "PATH";
} else if(buffer.charAt(start) == '?') {
result.host = result.user;
result.port = result.password;
result.user = "";
result.password = "";
section = "QUERY";
start ++;
} else if(buffer.charAt(start) == '@') {
section = "HOST";
start++;
} else {
result.password += buffer.charAt(start++);
}
} else if(section == "HOST") {
if(buffer.charAt(start) == '/') {
section = "PATH";
} else if(buffer.charAt(start) == ':') {
section = "PORT";
start++;
} else if(buffer.charAt(start) == '?') {
section = "QUERY";
start++;
} else {
result.host += buffer.charAt(start++);
}
} else if(section == "PORT") {
if(buffer.charAt(start) = '/') {
section = "PATH";
} else if(buffer.charAt(start) == '?') {
section = "QUERY";
start++;
} else {
result.port += buffer.charAt(start++);
}
} else if(section == "PATH") {
if(buffer.charAt(start) == '?') {
section = "QUERY";
start ++;
} else {
result.path += buffer.charAt(start++);
}
} else if(section == "QUERY") {
result.query += buffer.charAt(start++);
}
}
if(section == "PROTOCOL") {
result.host = result.protocol;
result.protocol = "http";
} else if(section == "AFTER_PROTOCOL") {
throw new ParseException("Invalid url");
} else if(section == "USER") {
result.host = result.user;
result.user = "";
} else if(section == "PASSWORD") {
result.host = result.user;
result.port = result.password;
result.user = "";
result.password = "";
}
return result;
}
function ParseException(description) {
this.description = description;
} |
| MidiMagic | May 19th, 2007 8:50 pm | |
| Re: What do you use to parse the url?
I don't unserstand why the Javascript needs to know the url of the calling page. Doesn't the person who wrote both of them already know that? |
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