error C2064: term does not evaluate to a function taking 1 arguments
 

Hi, I'm using Microsoft Visual C++ and I keep getting this error referring to this one line in my main file. The line of error is in bold.

Header file
[php]
int f (int n);

double e (double accuracy);

double exp (double expo, double exaccuracy);
[/php]

Computation file
[php]


#include "wong_header.h"

int f(int n)
{
int t = 1;
while (n >= 1)
{
t = t * n--;
}
return t;
}

double e (double accuracy)
{
accuracy = accuracy - 1;
double fac = 1;
double ee = 0;
while (accuracy >= 1)
{
fac = fac * accuracy;
ee = ee + (1/(fac));
accuracy--;
}
return ee;
}

double exp (double expo, int exaccuracy)
{
exaccuracy = exaccuracy - 1;
double value;
double fact = 1;
double exo = 0;
while ((expo >=0)&&(exaccuracy >=1))
{
value = expo * exaccuracy;
fact = fact * exaccuracy;
exo = exo + (value/fact);

exaccuracy--;

}
return exo;
}
[/php]


main file

#include <iostream>

#include <fstream>

#include <cstdlib>

#include <string>

#include <iomanip>

using namespace std;

#include "wong_header.h"





int main()

{

        string command;

        int arg1;

        double earg2;

        double exarg4, exarg5;

        int result;

        double eresult, exresult;



        ifstream fin ("input.txt");        //reads from file input.txt

        if (!fin)                                        //checks input file 

        {        

                cerr <<"Cannot open the file input.txt\n";

                return 0;

        }



        ofstream fout("out.txt");        //output stream 

        if (!fout)                                        //check if output file 

        {                                                        //was opened successfully

                cerr <<"Cannot open the file out.txt\n";

                return 0;

        }





        while(!fin.eof())        //it will read line after line until the program ends

        {

                fin >> command;



                int f = atoi (command.c_str());

                if (command == "f")

                {

                        fin >> arg1;

                        result = f(arg1);



                        cout << "factorial of " << arg1 << "= " << result << "\n";

                        fout << "factorial of " << arg1 << "= " << result << "\n";

                }



                else if (command == "!")

                {

                }



                else if (command == "e")

                {

                        fin >> earg2;

                        eresult = e(earg2);



                        cout << "e with the accuracy of " << earg2 << " is " << eresult<< "\n";

                        fout << "e with the accuracy of " << earg2 << " is " << eresult<< "\n";

                }



                else if (command == "exp")

                {

                        fin >> exarg4, exarg5;

                        exresult = exp(exarg4, exarg5);

                        

                        cout <<"The value of e^x with e being " <<exarg4<<" and x being " <<exarg5<< "is\n";

                        cout << exresult <<"\n";

                        fout <<"The value of e^x with e being " <<exarg4<<" and x being " <<exarg5<< "is\n";

                        fout << exresult <<"\n";

                }

                else

                {

                }

        }

        fin.close();

        fout.close();



        return 0;

}

Can someone help me figure out what I'm doing wrong?

Re: error C2064: term does not evaluate to a function taking 1 arguments
 

which line is in bold ? they all look bold to me. how about adding some comments that point to the line

... <<< this line is the error 

I think its better to use code tags when posting code, not php tags.

Re: error C2064: term does not evaluate to a function taking 1 arguments
 

Sorry, here it the main file again:

#include <iostream>

#include <fstream>

#include <cstdlib>

#include <string>

#include <iomanip>

using namespace std;

#include "wong_header.h"





int main()

{

        string command;

        int arg1;

        double earg2;

        double exarg4, exarg5;

        int result;

        double eresult, exresult;



        ifstream fin ("input.txt");        //reads from file input.txt

        if (!fin)                                        //checks input file 

        {        

                cerr <<"Cannot open the file input.txt\n";

                return 0;

        }



        ofstream fout("out.txt");        //output stream 

        if (!fout)                                        //check if output file 

        {                                                        //was opened successfully

                cerr <<"Cannot open the file out.txt\n";

                return 0;

        }





        while(!fin.eof())        //it will read line after line until the program ends

        {

                fin >> command;



                int f = atoi (command.c_str());

                if (command == "f")

                {

                        fin >> arg1;

                        result = f (arg1);//THIS LINE IS THE ERROR



                        cout << "factorial of " << arg1 << "= " << result << "\n";

                        fout << "factorial of " << arg1 << "= " << result << "\n";

                }



                else if (command == "!")

                {

                }



                else if (command == "e")

                {

                        fin >> earg2;

                        eresult = e(earg2);



                        cout << "e with the accuracy of " << earg2 << " is " << eresult<< "\n";

                        fout << "e with the accuracy of " << earg2 << " is " << eresult<< "\n";

                }



                else if (command == "exp")

                {

                        fin >> exarg4, exarg5;

                        exresult = exp(exarg4, exarg5);

                        

                        cout <<"The value of e^x with e being " <<exarg4<<" and x being " <<exarg5<< "is\n";

                        cout << exresult <<"\n";

                        fout <<"The value of e^x with e being " <<exarg4<<" and x being " <<exarg5<< "is\n";

                        fout << exresult <<"\n";

                }

                else

                {

                }

        }

        fin.close();

        fout.close();



        return 0;

}

Re: error C2064: term does not evaluate to a function taking 1 arguments
 

                int f = atoi (command.c_str());

                if (command == "f")

                {

                        fin >> arg1;

                        result = f (arg1);//THIS LINE IS THE ERROR



                        cout << "factorial of " << arg1 << "= " << result << "\n";

                        fout << "factorial of " << arg1 << "= " << result << "\n";

                }

Since you have a local variable called f, you can't call the function f(). Give them different names, like f_ret and func().

Re: error C2064: term does not evaluate to a function taking 1 arguments
 

thanks :)

Re: error C2064: term does not evaluate to a function taking 1 arguments
 

Heh, that was post 100 for him. I feel so honored. It's not reading the input.txt file though. Where do I put the input fine so my program can read it?

Re: error C2064: term does not evaluate to a function taking 1 arguments
 

Generally, your input.txt should go in the same place as your executable. If for some reason, this is causing you problems, or you do not know where the executable is, refer to the complete path of the txt file explicitly, for example, in DOS/Windows, you'd use

ifstream fin ("C:\\MyProgram\\input.txt");

the double-backslash is necessary, since the file location is a string (and '\\' is the escape character for a single backslash)

Re: error C2064: term does not evaluate to a function taking 1 arguments
 

Thanks, but I already handed my project in... incorrectly. I probably got

probably (grade < 70)
{
cout << "Isuck because you failed" <<endl;
}