Need a little guidance??
 

Can u anybody of u explain me how the following statement works??
y=x++<=5;:!:

Re: Need a little guidance??
 

If x is less than or equal to 5, y is set to 1 -- otherwise y is set to 0; x is then incremented.

But better would be for you to ask, "I think that this statement does [...]. Is this correct?" Or at least provide a (minimal, but complete and compileable) snippet that shows the full context.

Re: Need a little guidance??
 

Is x incremented before or after the result of the comparison is assigned to y? Correct me if I am wrong in the explaination below.
y=x++<=5; is equivalent to y=(x++<=5);.
The part inside the brackets should be evaluated first. So doesn't that mean the binary comparison and the ++ should also be evaluated before the assignment?

Re: Need a little guidance??
 

After.No.

Re: Need a little guidance??
 

So the error was this statement?
y=x++<=5; is equivalent to y=(x++<=5);.

Re: Need a little guidance??
 

No.
http://c-faq.com/expr/precvsooe.html

Re: Need a little guidance??
 

This is the case of post incrementation so increment is done after the comparision.

Re: Need a little guidance??
 

I know that it is done after the comparison. I wanted to know if it was done after or before the assignment.

Re: Need a little guidance??
 

My knowledge suggest that asignment is done before the incrementation.

Re: Need a little guidance??
 

I'll go out on a limb a little (and search more later) and say that it is done after the comparison and before the assignment.