setprecision
 

I have #include<iomanip> header also and it's still not working.I am getting 2 dec places but it's .00 Why is that?Please help.
here is the code
cout << showpoint << fixed << setprecision (2);
cout<<"The Mean is "<<mean<<endl;


also this code is not working ,when I use the [ ] at the end,I am getting an error so I am using () instead but the calculation is incorrect.Please help

float var=((num[0]-mean)*pow(num[0]-mean,2) + (num[1]-mean)*pow(num[1]-mean,2) + + (num[2]-mean)*pow(num[2]-mean,2))/ (num[arraysize-1]);

#include <iostream>
#include<iomanip>
#include <cmath>
usingnamespace std;
int main()
{

char choice;
const int arraysize=20;
int num[arraysize];
do
{

cout<<"I will give you the Sum,Mean,Var & the Std Dev of any series of numbers?Y/N:"<<endl;
cin>>choice;
if(choice =='Y'||choice =='y')
{

cout<<"How many numbers will you enter? (up to 20)?"; cin>>num[arraysize];
for (int j=0;j<num[arraysize];j++)
{
cout<<"Enter Number"<<j+1<<":"; cin>> num[j];
}

cout << " You have entered the following:"<<endl;
for (j = 0; j < num[arraysize]; j++)
{

cout << num[j]<<" ";
}
int sum=0;
for (j=0;j<num[arraysize];j++)
sum+= num[j];
cout<<"\nThe Sum is "<<sum<<endl;
float mean= (sum/num[arraysize]);
cout << showpoint << fixed << setprecision (2);
cout<<"The Mean is "<<mean<<endl;
float var=((num[0]-mean)*pow(num[0]-mean,2) + (num[1]-mean)*pow(num[1]-mean,2) + + (num[2]-mean)*pow(num[2]-mean,2))/ (num[arraysize-1]);
cout << showpoint << fixed << setprecision (2);
cout<<"The Varience is " <<var<<endl;
float sqrtvar=sqrt(var);
cout << showpoint << fixed << setprecision (2);
cout<<"The Standard deviation is "<<sqrtvar<<endl;
}
}while(choice!='N'&& choice!='n');
return 0;

}

Re: setprecision
 

If you want help you need to post the whole code. Read this

setprecision
 

entire code

#include <iostream>
#include<iomanip>
#include <cmath>
usingnamespace std;
int main()
{

char choice;
const int arraysize=20;
int num[arraysize];
do
{

cout<<"I will give you the Sum,Mean,Var & the Std Dev of any series of numbers?Y/N:"<<endl;
cin>>choice;
if(choice =='Y'||choice =='y')
{

cout<<"How many numbers will you enter? (up to 20)?"; cin>>num[arraysize];
for (int j=0;j<num[arraysize];j++)
{
cout<<"Enter Number"<<j+1<<":"; cin>> num[j];
}

cout << " You have entered the following:"<<endl;
for (j = 0; j < num[arraysize]; j++)
{

cout << num[j]<<" ";
}
int sum=0;
for (j=0;j<num[arraysize];j++)
sum+= num[j];
cout<<"\nThe Sum is "<<sum<<endl;

float mean= (sum/num[arraysize]);
cout << showpoint << fixed << setprecision (2);
cout<<"The Mean is "<<mean<<endl;
//not working

float var=((num[0]-mean)*pow(num[0]-mean,2) + (num[1]-mean)*pow(num[1]-mean,2) + + (num[2]-mean)*pow(num[2]-mean,2))/ (num[arraysize-1]);
cout << showpoint << fixed << setprecision (2);
cout<<"The Varience is " <<var<<endl;
//not working
float sqrtvar=sqrt(var);
cout << showpoint << fixed << setprecision (2);
cout<<"The Standard deviation is "<<sqrtvar<<endl;
//not working
}

}while(choice!='N'&& choice!='n');
return 0;

}

Re: setprecision
 

lovely code -- but what is your question ? please edit your post to include code tags.

Re: setprecision
 

Please explain the problem clearly so that we can help you out. Post your entire code along with the problems you are encountering.. whether it is compile time error or run time error or the program is not working as expectd and so on. Maybe then we would be able to help you out.

Re: setprecision
 

I suggest you do a google search of setprecision and pow.

I think pow expects a double somewhere. So you'll have to write pow(2,3) and pow (2.0,3.0) or something? Not to sure.