help with conversion calculator
 

this code to convert pounds to barbados dollars given a constant rate the price cannot go over $100 when i first run it and input a number under 100 it tells me that it is invalid and sometimes i get nothing at all. Can neone tell me why?

/* This Program converts Pounds Sterling to Barbados Dollars*/

# include <stdio.h>



int main ()



{

        float Pds, Bds; /* Declare Variables*/

        const float Rate =3.75;



        printf("Enter the Price in Pounds Sterling\n"); /*Prompt User*/

        scanf_s("%f", &Pds);



   while(Pds >100);/* finds illegal value*/

   {

    printf("Error your price cannot be greater than $100\n");

        printf("Please Enter another\n");

        scanf_s("%f",&Pds);

   }



     Bds=Pds*Rate;



     printf("Price in Barbados Dollars=%.2f",Bds);



        

        return 0;



        }

Re: help with conversion calculator
 

stop using scanf() because it may corrupt the input buffer and leave keys in the keyboard buffer. use fgets() instead

float num;

char buf[16];

printf("blabla");

// get input from user

fgets(buf,sizeof(buf),stdin);

// convert to float

num = atof(buf);

Re: help with conversion calculator
 

Hm did U got corrupted code and your task is to fix it?
No?!?! Ok then just remove ; after while loop.

Re: help with conversion calculator
 

yeah it was the semi colon, thx a bundle can i ask why it did that tho?

Re: help with conversion calculator
 

>> while(Pds >100);

that is an infinite loop because of the semicolon at the end. Your program will never stop executing that loop because the value os Pds never changes. This is a common error that everybody counters on occasion due to carelessness.

Re: help with conversion calculator
 

while ( Pds > 100 ) ; is equivalent to

while ( Pds > 100 )

{

   // sit back and enjoy baby 

}

Like Mr. Dragon said the variable which controls the run of your "While " loop never changes and so it goes on for infinity.