Clarity...
 

hi just have a question to make sure i understand it. i'm doing the exercises in my book and it says i should create a program which will roll 2 dice and produce a random number then adds the sum of the outcomes.

 public class RollDice

{

    /* This program simulates rolling a pair of dice.

        The number that comes up on each die is output,

        followed by the total of the two dice.

    */

    

    public static void main (String[] args)

    {

        int die1;    //The number on the first die.

        int die2;    //The number on the second die.

        int roll;    //The total roll (sum of the two dice).

        

        die1 = (int) (Math.random() *6) + 1;

        die2 = (int) (Math.random() *6) + 1;

        roll = die1 + die2;

        

        System.out.println("The first die comes up " + die1);

        System.out.println("The second die comes up " + die2);

        System.out.println("Your total roll is " + roll);

        

    }    //end man()

}    //end of class

now this is all okay but when i remove the +1 there isnt any difference. i just want to know if removing the +1 will cause any problem on the program. if not...how about if i'm writing a longer program, will there be any implication?

Thanks

Re: Clarity...
 

if take out +1 this will generate numbers in the interval between 0-5 inclusive

Re: Clarity...
 

Thanks.

Re: Clarity...
 

Yeh, thats right, to be precise...
Math.random() generates a number between 0 and 1 inclusive, the chance of getting 0 or 1 is almost 0 though.
so suppose you wanted 1 to 6, first you mulitply by 6,
this gives you a number in the range 0-6, eg 5.92367236746.
Then converting to an int, will always give you either 0,1,2,3,4,5.
So just add 1, to get 1 to 6.

Re: Clarity...
 

Thanks guys. And might i add...you guys post replies quite fast! cool!