Hash Table display problem
 

I wrote a hash table that takes a char as a key and for a test I am using a string for my value. It uses a linked list. But I am having a problem displaying the value. I have a function that displays the key correctly but the value is displayed as garbage. I am prety sure it is this one method that is causing it to display incorrectly but it complies and runs fine, i am just not sure why this does not work. Here is the method I think is not working and I am attaching the entire sample program as a txt file if someonecan take a look. I a little stuck on this.

bool Hashtable::get(char *key, string value)

{

    METADATA* temp = find(key);

    if(temp == NULL)

    {

        value = "";

        return false;

    }

    else

    {

        value = temp->value;

        return true;

    }

}

Here is my Display Function and it calls this function so I am assuming that for some reason the data is not bein copied correctly.

void displayAll(Hashtable *hashtable)

{

    char key[SIZE_KEY];

    char value[SIZE_VALUE];

    cout<< "\nCurrent nodes in hashtable: " << endl;

    hashtable->initIterator();

    while(hashtable->hasNext())

    {

        hashtable->getNextKey(key);

        hashtable->get(key, value);

        cout << "key: " << key << "\tvalue : " << value << endl;



    }

}

Thanks

Re: Hash Table display problem
 

value is an array. When you pass it as the second argument to get, it acts as the initializer for the std::string parameter. You've lost your reference, and any changes to the parameter will not be reflected back in displayAll. Change value to a string and pass it by reference to get.

Re: Hash Table display problem
 

Ahh thank you. I did that and it worked perfectly.