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| Please Help Dynamic Memory Allocation. Each of the following program segments might have syntax, logic or other kinds of errors. If there are errors, correct, otherwise answer "no error". Assume all function headers are correct. Function copy_array receives an integer array a and its size length, as parameters. It copies the array a into another integer array b newly created, and returns the address of the new array b. int *copy_array ( int a[], int length ) CORRECT: int *copy_array ( int a[], int length ) My Question is that is dynamic memory allocation really necessaryÉ since you already know the size of the array which is being passed by the caller. Also can some someone explain each step of line 1 and 2. Thanks in advance. |
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| Re: Please Help Dynamic Memory Allocation. >is dynamic memory allocation really necessaryÉ since you already >know the size of the array which is being passed by the caller Really? How do you know? If you're talking about the length parameter, then yes, dynamic allocation really is necessary because array sizes must be compile-time constants. This isn't legal C++: int *copy_array ( int a[], int length )>Also can some someone explain each step of line 1 and 2. Line 1 allocates length * sizeof(int) bytes and assigns it to b. Line 2 allocates length * sizeof(int) bytes and assigns it to b. Both lines are incorrect and won't compile as C++ because C++ doesn't support an implicit conversion from void*, and both calloc and malloc return void*. |
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| Re: Please Help Dynamic Memory Allocation. What about in C. É Quote:
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| Re: Please Help Dynamic Memory Allocation. Quote:
>> because array sizes must be compile-time constants Not any more -- C99 has changed that for C language, not sure if it will also apply to C++ or not. |
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| Re: Please Help Dynamic Memory Allocation. >Not any more -- C99 has changed that for C language While C++ has a certain measure of compatibility with C, it's with C89, not C99. In C++, array sizes must be compile-time constants. |
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