'; echo '	'.$year.' '.$make.' '.$model.' '.$miles.' '.$comment.' '; echo ' '; echo ' '; echo ' '; echo '	'.$option1.' '.$option2.' '.$option3.' '; if($option4 != "") echo $option4.' '; if($option5 != null) echo $option5.' '; if($option6 != null) echo $option6.' '; if($option7 != null) echo $option7.' '; if($option8 != null) echo $option8; echo '

'; echo '	'.$year.' '.$make.' '.$model.' '.$miles.' '.$comment.' '; echo ' '; echo ' '; echo ' '; echo '	'.$option1.' '.$option2.' '.$option3.' '; if($option4 != "") echo $option4.' '; if($option5 != null) echo $option5.' '; if($option6 != null) echo $option6.' '; if($option7 != null) echo $option7.' '; if($option8 != null) echo $option8; echo '

DaniWeb IT Discussion Community - MySQL

netbeans6.0 & MySQL database

ceyesuma — Thu, 15 May 2008 10:08:47 GMT

Is this an appropriate place to submit a question concerning netbeans and creating queries?

Export and Import of database errors, please advise.

Kraai — Thu, 15 May 2008 08:15:23 GMT

I am helping a website owner to transfer a site to new servers. All site files have been uploaded onto the new server, only thing left is the database.

In phpmyadmin, when I try to export the DATABASE to my local PC, using zip or gzip to compress, as this is a large database, the file doesn't want to uncompress on my local pc, I get an error message that it may be corrupt?

Then I exported the database without compressing it, and it downloaded without any problems.

As I am realy very novice in this, and only have a basic knowledge how to import this database from my local PC to the new server, using phpmyadmin, the first problem was that phpmyadmin only allows 51 mb to import this way, and this database is about 90 mb. I am very unlitterate in doing command line queries to do this import, so I contacted the support of the new host to help out, and they said I can upload the database via ftp to the server, and they wil install it from there.

I then uploaded the uncompressed .sql text file to a folder, via ftp, using binary mode.

When the host tried to install it, they got an error message in the syntax at a certain line, and asked me to correct it. I have no idea how to, as this database is just what came from the old server, nothing changed to it.

Is there any help or hope for me on this one?

Edit:

The full error message the host got was:

[root@cayenne /home/kletsker/mysqldump]# mysql kletsker_kletskerk < localhost.sql ERROR 1064 (42000) at line 89499: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''[quote="Barend":3v' at line 1

How do you use output from linked server query?

kbrown123 — Wed, 14 May 2008 20:25:32 GMT

I am reading records from a linked server table, and trying to use the output in the next update statement, not on the linked server. I am assigning it to a declared variable. The file is being updated with NULL, instead of the correct check number. Any help???

Example code:

DECLARE
@CHECK   VARCHAR(8)
@TSQL    varchar(8000)
 
SELECT @TSQL = 'SELECT keyfield FROM OPENQUERY(linkedserver, 
      ''SET '+@CHECK+'= select keyfield from library.file WHERE document=12345)'
 
EXEC (@TSQL)
 
UPDATE mainlibrary.file SET Keyfield2=@CHECK WHERE document=12345
 
END

How to stop iterating through a table?

tefflox — Wed, 14 May 2008 17:56:01 GMT

Here is the code. For a short time, I will leave the test results up at superiorminitrucks.com/inventory

Clearly, I need to stop it from displaying the final entry twice..

Thanks in advance..

        


                $db_connection = @mysql_connect("######", "#####", "####");

                

                if (!$db_connection) 

                        exit();        

                        

                mysql_select_db("tefflox", $db_connection);



                $result = mysql_query("SELECT * FROM trucks");



                        while($row = mysql_fetch_array($result)) {

                          if($row['id']){

                                $lightbox1 = $row['relpath-box1'];

                                $lightbox2 = $row['relpath-box2'];                        

                                $lightbox3 = $row['relpath-box3'];                        

                                $lightbox4 = $row['relpath-box4'];

                                $primary   = $row['relpath-primary'];

                                $gallery1  = $row['relpath-gallery1'];

                                $gallery2  = $row['relpath-gallery2'];                                                

                                $gallery3  = $row['relpath-gallery3'];                        

                                $year      = $row['year'];

                                $make      = $row['make'];                        

                                $model     = $row['model'];                        

                                $miles     = $row['miles'];

                                $comment   = $row['comment'];

                                $option1   = $row['option1'];

                                $option2   = $row['option2'];

                                $option3   = $row['option3'];

                                $option4   = $row['option4'];

                                $option5   = $row['option5'];

                                $option6   = $row['option6'];

                                $option7   = $row['option7'];

                                $option8   = $row['option8'];

                          }                                                                                                                                        



                

        echo("\n");

        echo("  \n");

        echo("    \n");

        echo("  ". $year . " " . $make . " " . $model . "

". $miles ."
". $comment ."

\n");

        echo("    \n");

        echo("    \n");

        echo("    \n");          

        echo("  \n");

        echo("  ". $option1 ."
". $option2 ."
". $option3 ."

". $option4 ."
". $option5 ."
". $option6 . "
". $option7 ."
". $option8 ."\n");

        echo("\n\n");                                

                                

                }

        

                

                mysql_close($db_connection);

                        

        ?>

realtime query without cronjob

forzadraco — Wed, 14 May 2008 02:35:54 GMT

how to copyng data from another database postgre to mySQL database without cronjob with realtime... thanks

Please help

tefflox — Tue, 13 May 2008 17:16:15 GMT

Please tell me what I'm doing wrong. The sql query is in bold.


////////////////////////////////////////////////////////////////////////////////

//

// SECRET PAGE

//

//   Invokes require_authentication() to ensure that the user is authenticated

//     

//////////////////////////////////////////////////////////////////////////////// 

require("common.php");

require_authentication();

session_start(); ?>





  

    Preview Update

  

 

                
       

            $data = $_SESSION['data'];



        

                  $year    = $_POST['year'];

                  $make    = $_POST['make'];

                  $model   = $_POST['model'];

                  

                  $miles   = $_POST['miles'];

                  $comment = $_POST['comment'];

                  

                  

                  $option1 = $_POST['option1'];

                  $option2 = $_POST['option2'];

                  $option3 = $_POST['option3'];



                  $option4 = $_POST['option4'];                  

                  $option5 = $_POST['option5'];                  

                  $option6 = $_POST['option6'];                  

                  $option7 = $_POST['option7'];                  

                  $option8 = $_POST['option8'];                  





        $update = array(0 => $data[0], $data[1], $data[2], $data[3], $data[4], $data[5], $data[6], $data[7], $year, $make, $model, $miles, $comment, $option1, $option2, $option3, $option4, $option5, $option6, $option7, $option8);

                  



                echo '';       

        echo '    ';

        echo '  ';

        echo '    ';

        echo '      ';

        echo '    ';

            echo '  ';

        

   

        

  

               

echo ' ';

        echo '     '.$year.' '.$make.' '.$model.'

'.$miles.'
'.$comment.'

 ';

        echo '        ';

        echo '        ';

        echo '        ';        

        echo '     '.$option1.'
'.$option2.'
'.$option3.'

';

        if($option4 != "")

                echo $option4.'
';

        if($option5 != null)

                echo $option5.'
';

        if($option6 != null)

                echo $option6.'
';

        if($option7 != null)

                echo $option7.'
';

        if($option8 != null)

                echo $option8;                                                        

                

                

                echo '
';

echo '


';



                        

                        echo '';        

                        echo '';

                        echo ' (not yet operational)
';        

                        echo '
';        

                                

                        







        $db_connection = @mysql_connect("-----------.--------.net", "--------", "---------");

        if (!$db_connection) {

          echo( "Unable to connect to the database server at this time.
" );

          exit();

        }        

        

        $db = @mysql_select_db("-----------", $db_connection);

        

        if(!$db) {

          echo( "Unable to locate the database at this time.
" );

      exit();

        }

        

        

    if ("SUBMIT" == $validated_confirmed_update) {

      $sql = "INSERT INTO trucks (relpath-box1, relpath-box2, relpath-box3, relpath-primary, relpath-gallery1, relpath-gallery2, relpath-gallery3, year, make, model, miles, comment, option1, option2, option3, option4, option5, option6, option7, option8) VALUES (".$data[0].", ".$data[1].", ".$data[2].", ".$data[3].", ".$data[4].", ".$data[5].", ".$data[6].", ".$data[7].", ".$year.", ".$make.", ".$model.", ".$miles.", ".$comment.", ".$option1.", ".$option2.", ".$option3.", ".$option4.", ".$option5.", ".$option6.", ".$option7.", ".$option8.")"; 

                         

                                         

    mysql_query($sql);

 }

?>

Please help populate my first functional database.

tefflox — Tue, 13 May 2008 03:58:57 GMT

I am able to connect to the database and located the table. I am unable to populate the db. Attached is a in image of the phpmyadmin trucks table structure. Please help. I am excited to be so close to getting it right.

                        

                        echo '';        

                        echo '';

                        echo '
';        

                        echo '
';        

                                

                        







        $db_connection = @mysql_connect("----------------------.net", "--------------", "----------------");

        if (!$db_connection) {

          echo( "Unable to connect to the database server at this time.
" );

          exit();

        }        

        

        $db = @mysql_select_db("---------", $db_connection);

        

        if(!$db) {

          echo( "Unable to locate the database at this time.
" );

      exit();

        }

        

        

    if ("submit" == $validated_confirmed_update) {

      $sql = "INSERT INTO trucks SET " .

             "relpath-box1='$data[0]', " .

             "relpath-box2='$data[1]' ," .

                         "relpath-box3='$data[2]' ," .

                         "relpath-box4='$data[3]' ," .

                         "relpath-primary='$data[4]' ," .

                         "relpath-gallery1='$data[5]' ," .

                         "relpath-gallery2='$data[6]' ," .

                         "relpath-gallery3='$data[7]' ," .

                         "year='$year' ," .

                         "make='$make' ," .

                         "model='$model' ," .

                         "miles='$miles' ," .

                         "comment='$comment' ," .

                         "option1='$option1' ," .

                         "option2='$option1' ," .

                         "option3='$option1' ," .

                         "option4='$option1' ," .

                         "option5='$option1' ," .

                         "option6='$option1' ," .

                         "option7='$option1' ," .

                         "option8='$option1'  " ;

                         

                                         

    mysql_query($sql);

 }

The stuff preceding the above....

  

 

                
       

            $data = $_SESSION['data'];



        

                  $year    = $_POST['year'];

                  $make    = $_POST['make'];

                  $model   = $_POST['model'];

                  

                  $miles   = $_POST['miles'];

                  $comment = $_POST['comment'];

                  

                  

                  $option1 = $_POST['option1'];

                  $option2 = $_POST['option2'];

                  $option3 = $_POST['option3'];



                  $option4 = $_POST['option4'];                  

                  $option5 = $_POST['option5'];                  

                  $option6 = $_POST['option6'];                  

                  $option7 = $_POST['option7'];                  

                  $option8 = $_POST['option8'];                  





        $update = array(0 => $data[0], $data[1], $data[2], $data[3], $data[4], $data[5], $data[6], $data[7], $year, $make, $model, $miles, $comment, $option1, $option2, $option3, $option4, $option5, $option6, $option7, $option8);

                  



                echo '';       

        echo '    ';

        echo '  ';

        echo '    ';

        echo '      ';

        echo '    ';

            echo '  ';

        

   

        

  

               

echo ' ';

        echo '     '.$year.' '.$make.' '.$model.'

'.$miles.'
'.$comment.'

 ';

        echo '        ';

        echo '        ';

        echo '        ';        

        echo '     '.$option1.'
'.$option2.'
'.$option3.'

';

        if($option4 != "")

                echo $option4.'
';

        if($option5 != null)

                echo $option5.'
';

        if($option6 != null)

                echo $option6.'
';

        if($option7 != null)

                echo $option7.'
';

        if($option8 != null)

                echo $option8;                                                        

                

                

                echo '
';

echo '


';

Attached Images

db-table.jpg (132.9 KB)

PHP in MySQL Trigger

veledrom — Mon, 12 May 2008 14:56:34 GMT

Hi guys,

Can i run xxx.php page in a MySQL Trigger?

Thanks

How to Config MyOdbc 3.51 and MySql Server 7.0 to a Network Base

loveknights07 — Sat, 10 May 2008 11:34:30 GMT

Hi Everyone,

Good Day,,

can you help me to config mysql server to be able for me to connect to it thru a network.

for example the mysql server is on the other pc and i am using a software in other pc.
how can i connect to it.?

thanks for help..

loveknights07

ODBC configuration

evios — Fri, 09 May 2008 00:40:41 GMT

Well, i am facing this problem when i try to configure my ODBC 3.51 Driver.
I had successfully installed MySQL. Then i try to install and configure my ODBC 3.51 driver. I add a new user DSN, filling with the correct username and password, with the data source name. However when i scroll down for the database, i geth the error message as shown.:
Request returned with SQL_ERROR
I already turn off my firewall. Anyone can help? Thanks.

UDF in MySQL

tanha — Thu, 08 May 2008 20:30:28 GMT

Hi.
I want to know how it is possible to write your own function "UDF" in MySQL? and how use that UDF in MySQL?

mySQL TRIGGER problem

M3nTaL — Thu, 08 May 2008 10:32:36 GMT

Hello,

I'm having some sintax problems using PL/SQL in mySQL TRIGGERS.. I need some help please :).
Here is the code:

CREATE TRIGGER modificou

   AFTER UPDATE ON monitor

   FOR EACH ROW

 BEGIN

   IF NOT EXISTS(SELECT estado_tmp FROM alteracoes WHERE id_tmp = OLD.id)

   THEN

       INSERT INTO alteracoes VALUES(OLD.id,NEW.estado);

   ELSE

       UPDATE alteracoes SET estado_tmp = NEW.estado WHERE id_tmp = OLD.id;

   END IF;

 END modificou;

What could be wrong?? For testing I'm using phpmyadmin 2.11.1

Thanks

MySQL Error 1064 when DELETEing

ray_broome — Wed, 07 May 2008 18:21:14 GMT

I'm trying to carry out the following delete statements

DELETE FROM images AS i WHERE i.image_id = 803 AND i.plant_num = 2277 LIMIT 1

DELETE FROM images AS i WHERE i.image_id = 804 AND i.plant_num = 2277 LIMIT 1

DELETE FROM images AS i WHERE i.image_id = 805 AND i.plant_num = 2277 LIMIT 1

but i am getting the error:

1064: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'AS i WHERE i.image_id = 803 AND i.plant_num = 2277 LIMIT 1; DELETE FROM images A' at line 1

any idea what is causing this because everything looks okay to me.

Thanks in advance

Having issues on MYSQL from one Domain to another

freeosin — Tue, 06 May 2008 20:28:35 GMT

Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in C:\Inetpub\vhosts\thepinflow.com\httpdocs\staff\checklogin.php on line 12
Wrong Username or Password

That is the error message I am recieving.

I was using another website to host a PHP/SQL website before,
currently located at: http://www.blackairplane.com/Pinflow/index.php
which works. When I copied all the files over completely and then tried
to run it on the http://staff.thepinflow.com/ site (under the 1&1
purchased domain), and try to login, I return the following error:
Warning: mysql_num_rows(): supplied argument is not a valid MySQL result
resource in

C:\Inetpub\vhosts\thepinflow.com\httpdocs\staff\checklogin.php on line
12Wrong Username or Password..

yet it all works fine on my other domain www.theblackairplane.com as mentioned above...

I really need help on this as I am paying 40 bucks a month and not
being able to use the site as intended. How could just transferring the
site over from one domain to the other make it not work?

Insert doesn't do what it's supposed to

Icetigris — Tue, 06 May 2008 08:37:26 GMT

I have a ton of inserts in an sql file that look like this:

INSERT INTO grades (GWid, classid, semester, year, grade, required) 

VALUES(100000089, 'CS210', 'B', 'fall', '2006', 'yes');

but when I get my filled tables, the semester and grades are all null and the year is 0000. Any explanations as to why this would be happening?

I'm using phpMyAdmin 2.6.4-pl4 with MySQL 3.23.32 (maybe higher). It's on a university server so I don't have any choice in the matter or privileges to change anything.
-----------------------

Crap, I just realised that the values are in the wrong order. Problem solved. Tiiiiired...