ensure that you don't have any whitespace after the closing php '?>' tag in your include files and that you are not echoing or printing anything prior to sending headers with the header() function....

you want pagination.

check out a couple of scripts in the snippets section...

http://www.daniweb.com/code/snippet341.html

http://www.daniweb.com/code/snippet612.html

pagination is pretty...

try specifying method='POST" in all of of your <form> tags...like so:


<form name="pointofcontact" action = "saveproject.php" method="POST">


it seems like some of your forms are defaulting...

JavaScript would be the way to go.
You'll probably get better help in the JavaScript/AJAX/DHTML forum on this one.

I believe you can only use a write mode such as 'a+' with fopen on a remote file if using ftp:// as the protocol...even so, you would have to have appropriate ftp permissions to write/append. More...

Yes, this is where the issue lies. The onchange attribute of each of your select boxes is set to redirect to a page as soon as an option is selected. The page is determined by the selected option's...

you could use a for loop rather than a while statement. For example:


$howMany=$_POST["hmany"];

for($i=0;$i<=$howMany;$i++)
{
$rand=mt_rand(1,$_POST["dice"]);
echo "You rolled a...

actually, this will just print the value of $abc (nothing) with the value of $i appended to the end. If you have variables $abc1, $abc2, etc. , you will not get the value of those variables, you'll...

the modulus operator (%) takes the left side, divides it by the right side, and returns the remainder. So, 5%3 would result in two, since 5/3 yields a remainder 2.

If you are getting a division...

you were close here. Just a small change:

for($i=1; $i<=3; $i++)
{
echo $abc[$i];
}


or for unknown array size, use:

like the user said, if the POST variables aren't set, the code won't execute. Even if they are, the code won't execute the second time around if the user was validated on the first run, because your...

you'll get that warning when trying to call session_start after outputting content to the browser with something like echo or print, or if you have embedded PHP that calls a session_start following...

try encoding your str1 with encodeURIComponent

more about this at w3schools (http://www.w3schools.com/jsref/jsref_encodeURIComponent.asp)

the syntax of your query is ok. Something else is going on here. Can you post more code or any MySQL errors you are getting?

to encode it in php...


<?php

//encode input going in...
$encode = urlencode("in'out\"");

//decode output coming out...
$decode = urldecode($encode);

another way to tackle it would be...

echo '<td align=center style="width: 30px"><strong><a href="' . $link1 . '" style="color: red">CID</a></strong></td>';

echo "<td align=center style=\"width: 30px\"><strong><a href=\"$link1\" style=\"color: red\">CID</a></strong></td>";

'L' returns 1 if it is a leap year or 0 if it is not. Use 'Y' for 4-digit year.

<?php

//old time
$old_time = '2008-03-05 18:05:44';

//convert to UNIX timestamp
$timestamp = strtotime($old_time);

//fetch new format
$new_time = date('m-d-Y H:i:s' , $timestamp);

Working off the code sample in my earlier post...
Here would be one way to ensure the checkboxes were checked if they had chosen them previously...


//array to hold checkbox options...

mmmmmmm cookies...

<?php
//make a batch of cookies
//pass name of array as $batchName, and the values you wish to store as an array $valueArray
function batch_of_cookies($batchName,...

try changing your code like this:

while($row = mysql_fetch_array($resultmoto))
{
$data = $row[1];
$leg = $row[0];
$chart [ 'chart_data' ][ 0 ][ $bar ] = $data;

$chart [ 'chart_data' ][...

syntax is the same as c. for example:

<?php

for($i=0; $i < 50; $i++)
{
//skip numbers 4
if($i == 4)
{
continue;

echo your option tags inside of a select tag like this:


<select name="test" id="test">
<option value="value 1">option 1</option>
<option value="value 2">option 2</option>
<option...

also, just to make sure we're not missing something obvious here...you are saving the page as .php extension right?

you only have to use commas if you want commas to appear in the output



what part is not working, Everything seems to work when I run it...what are you trying to do?

like flow charts?

glad to be of assistance!

try these changes...I put some comments where I thought they might help you understand what I changed...

<?php

$accountname = $_POST['accountname'];
$phone = $_POST['phone'];
$fax =...

to do a site like that, you're going to need secure form processing, some database interactivity to store sales records and customer info, and some email scripts to communicate with your customers....

i assume you have root access to the server to set configurations etc....

I am not a phpmyadmin maestro, so you might be better off posting this in a linux/wamp forum depending on your server...

at the top of your config.php you start output buffering, but have commented it out:

//ob_start("ob_gzhandler");

that probably means that the script sends headers throughout it...you may want...

have you checked out the igoogle documentation ?

http://code.google.com/apis/gadgets/index.html

on line 53 you say:

die(echo($errors)[0] );

to take care of the parse error you can change this to :


die($errors[0]);

try modifying your code like this:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html>
<head>

<title> Test...

as nav33n pointed out, there are other issues going on in this script, but if you change your code like so, you should get the siri=xxx as you wanted...

foreach ($_POST[status_batch] as $key=>...

If you try to call session_start() after any content has been output to the page, you will get this error. Make sure that none of your included files are outputting any content to the page such as...

i usually just insert the path to the location of the image, so I'm not well versed in storing the actual image data in and retrieving it from the database...I stumbled across this tutorial on...

something along these lines...you'll need to tweak it to fit your script, but you should get the idea...

//connect to mysql with your variables here...
//execute your sql query(s), store result...

if (empty($name) || empty($email) || empty($comments)) {
header( "Location: $errorurl" );
exit ;
}




change the above code (starts on line 11) so that it looks like this: