int var = 10 ;
int *pvar = &var;
int **ppvar = &pvar;

here var is 10. and this will be stored in some memory say that is
1000 (i.e &var =1000)
so
var =10
&var =1000

where is your program-------->

what is the meaning of largest sum of contiguous integers.
i understood it as below. ( correct me if wrong )

consider the elements of the array are

-1, 2, -3, 2, 0, 5, -11

so the sums of...

Hello ,
i have read the manual page of alloca ,

it is documented there that "alloca works similar to the malloc but it allocates memory from stack and frees automatically.

i can't get how can...

Thank you Aia, Its cleared.

int getch(void);
returns an integer value
so whats the problem, atleast it should print some value.

i dont understand how not casting return value can avoid errors, please just brief about that.

function to display the floating number
the float numbers are stored in sign exponent mantissa fashion
furthur reading
http://steve.hollasch.net/cgindex/coding/ieeefloat.html

void test()
{
...

you are reading the file in wrong order

here is a sample

void read()
{
FILE *fp;
int x;
char t1[50],t2[50];
float f1,f2;

I think this will do..



int main()
{
int a[10]={12,15,19,27,20,31,45,54,59,90};
//int a[10]={1,2,3,3,5,6,7,8,9,10};
int flag;
flag=find_order(a,sizeof(a)/sizeof(a[0]));

pass the headers in the functions and return updated ones.

i dont understand your logic but here i am giiving mine.

this is not so efficient but will do the same work.


#include <cstdlib>
#include <iostream>
#include<cstdio>
using namespace std;...

every thing is correct except this

it is always false
if (loan=0)
cout << "Months to repay the loan =" << counter <<endl



it should be

I hope this will solve your problem

http://www.dreamincode.net/forums/showtopic74004.htm

i have come across this lines often in the forum.

but is it not a better idea/or method to use explicit type casting.

try your code with this input:

(i)
filepairs.txt:
This is line 1
This is line 2
This is line 3
This is line 4
This is line 5
This is line 6

for (counter1=0;counter1<row;counter1++)
{
*(ptrA+counter1)=(int*)(calloc(column,sizeof(int)));
*(ptrB+counter1)=(int*)(calloc(column,sizeof(int)));...

i dont know spanish but i hope u understand this..

the segments


if (archivopar!=EOF)


and

Thank you All for your time

i will do some research on these according to your suggestions and get back to you soon
:)

Thanks again.

Thanks for your response Dragon.

actually i work on linux OS and here i can find that read and write system calls are used as internal functions of scanf and printf.
( confused here on how the...

i googled for some time but dint find any use full rather related information about different OS system calls.

what i got was these below links but these are not having much related info.
...

Hi,
if any one has the idea of the internal system calls which gets activated by using high level statements ( like printf ,scanf or malloc and so on) please provide me the links or any related...

could you please provide me a small code snippet on how that can be done?
do we need to use pointer stuff..!



int main()
{
double nums[] ={16.32,-16.32};
int i=0;
...

i just had a glance at your code
you declared


int temp_1, temp_2, temp_3;



and used

decalre a union with one double value and char array of 8 bytes.
in Little Endian format , always the sign will be MSB.
so take 7th array, and perform AND operation with 1(char) left shifted 7...

instead of
p = malloc(length+1);
use

p = (char *) malloc(length+1);


that is not a error, its a warning from the compiler.

because malloc returns pointer to void type

start the main function

declare two int variables

int year, month;
read the year and month values
just a scanf statement with to arguments .

now starts the procedure:

printing till 10 starting from some n.( 0< n <=10 )

using while :
int main()
{
int num;
printf("enter number (0 < num <= 10)\n");
scanf("%d",&num);
while(num>0 && num <=10)
...

instead of checking
if(a>b && a>c)
if(b>a && b>c)
if(c>b && c>a)

you could use

void find_big( int, int, int, int* );
int main()
{

the below code will cover maximum combiantions

for ex:
..1

1..
.
\n
a.a
1..1..1.11

you could do that by following below

read count;

for(start = 1; start <= conut; start++)
putchar( start + '0' );
for(start = start -2; start > 0; start--)
putchar( start...

thanks for your patient description jason
ofcourse i am aware of that.

one change is needed in the jas's code ,

the prime numbers starts form 2 .
forgot to check for that !

any number divisible by itself and by 1 is a prime number.
it always have only two...

better you supply the code how you are passing the the arguments to functions or the main program

ya i got the warning with all these on.
"struct has no members"

thank you very much TOM.

by the way, i dont know what is -pedantic mean
i know
-Wall - enable all warnings
-ansi - i think...

for (int numExs; counter>0; counter--) // C4700 ERROR HERE {
if (numExs>0 && numExs<11)
{
cout<<"X";
}
...

while ( b>=0 && b<15 )


this is where its getting infinite
the value of b is always >0 according to your code

i think it works fine with the following changes
if(b>0 && b <=15)
{
if ( code

specify the requirements clearly :

what do you want to store in linked list numbers or names(strings).
if numbers are to be stored use scanf
else use fgets or
you can define one safe function...

/*
difference between %i ad %d

%i reads the value and it recognizes the value as what base
it is when we read the value as 023 (base 8) it is 19 (base 10)
and...

int main()
{
intialize an int variable with the inital value either zero or one
while( variable < maxvalue)
{
//maxvalue is 10 in your case
...