Tried installing it and...Well lets put it this way, if I wasn't so entrenched in Mandriva I would have switched.

I'm sure GCC will survive...dings and all

I did use -ansi -Wall

When I tried -ansi -Wall -pedantic it generated a warning but still compiled and ran without incident..

I tried compiling this with the GCC compiler and its works...so I tried compiling with the -S switch(Stop after the stage of compilation proper; do not assemble) and found it create a function...

Try adding this to your if statement:


if(str[i] == 'a')
{
a++;
}
else if(str[i] == 'b')
{
b++;

That would be a debugger your talking about...If you expect your IDE to come fully featured then it won't be lightweight....Can VIM use a debugger? I really don't know because I never tried...

I...

If you want simple and complex then try VIM...

No the code looks fine..If you want to optimizes try experimenting with the compiler's optimizing settings...

Also you may want to look up VLA or 'variable length arrays'

Its undeniable, the point you make.

Then why would you put it in your program?


#
const char *str = &part1; //LINE 28


You have const char *str and your assigning the address of struct parts to it without a cast..

I would use fwrite


fwrite(&part1, sizeof(struct parts), 1, fd);

Where fd = FILE *stream

Note...I tried the above code with a client program I have here and it worked...Meaning it send the data and the client received it...

I quickly tried this an it doesn't fail...Note I never worked with AF_INET6...Also i took the liberty of changing some of your constants..


#include <stdio.h>
#include <stdlib.h>
#include...

Try:


connectSocket= accept(listenSocket, NULL, NULL);


Also I would check if an error returned on the two lines


bind(listenSocket,(struct sockaddr*)&serverAddress,sizeof(serverAddress));

Try investigating order of operations

Not really sure what your question is...well beside the main homework question..

Dynamic array yes..Look up VLA - variable length arrays

I'm not really sure what your after...but you could try working with a marco..

Note - Marcos are processed by the preprocessor as well

The include statement is processed by the preprocessor so it can't be dynamically created in the executable...

If you want to do this try Dlls

What do you have so far?

Did you even look at what I posted?

He wanted to know why and that's probably why. One compiler set up the assembled code to read the values left to right and one set up the values to be read right to left. Like you said the language...

Because you don't set i back to 5


c=i++ + ++i + i++ + --i;
i = 5;////set i back to five
printf("\n%d",i++ + ++i + i++ + --i);
printf("\n%d",c);

It probably depends on how the compiler evaluates the expressions...left to right
or right to left...

check out what I did here, I put three fprintf lines in here to check the values you are entering in your char**...Also this program had many errors...It won't compile for me so I changed some of it...

fopen is defined as

FILE* fopen(const char *path, const char *mode);

and you have fopen (out, "w"); where out is FILE*.

No KDE is O.K. just different...I run KDE on my Slackware box

I'm not sure which compiler your using but you should engage your warnings...i.e. gcc has a switch setting -Wall which is "warn all" and it picked up this problem in the compile stage..

This function returns the address of the local variable str


char * leer()
{
char str[LONG], *p;
int c;
p = str;

while((c = getchar()) != EOF)

Or this one which is a little more exotic - the language lawyers should love this one


#include <stdio.h>
#include <stdlib.h>

void Test(char **cptr);

int main()
{

I have this much modified example that you could use for an example:


#include <stdio.h>
#include <stdlib.h>

char* Test();

int main()
{

I would investigate the compare opcode and jump equal, jump not equal opcodes

Try this link:
http://www.amd.com/us-en/Processors/DevelopWithAMD/0,,30_2252_875_7044,00.html

manual 3...

Right away I see some problems

void Test(char, int);

void Test(char *text, int *sizeptr)

Try defining your string "instruction" like below...
Also if you have errors in the future could you post them


/* Libraries */
#include <stdio.h>
#include <string.h>

char instruction[] =...

Try this link...it has it all broken down

http://makepp.sourceforge.net/1.19/makepp_tutorial.html

Here's a simple one:


#include <stdio.h>
#include <stdlib.h>

int main(int argc, char**argv)
{
fprintf(stdout, "ans->%u\n", 0xe5f6b7);
exit(EXIT_SUCCESS);

A very simple solution would be to read your character and then read the newline character into a dumby variable like


char ch, extrach;

fputs("enter a character->", stdout);
ch =...

Try looking at this simple version of what your doing


#include <stdio.h>
#include <stdlib.h>

int main()
{
char mych = 0;
fputs("enter a character->", stdout);

I added a fprintf function in your code...run and check the values of choice..


#include <stdio.h>
#include <stdlib.h>
#include <string.h>


void user()
{

What is this program supposed to do? If you could give us an example...say

When I run this program and I'm prompted for this and I press this - this happens, when in fact this should happen...I...