Thanks, that's stopped the first error.

However now an odd result has turned out. The script on its own gives the picture I linked to in my previous post.

However in the code when it's within...

Hey folks,

I'm working on animating gifs in GD. I've adapted the use of the GIFEncoder class from phpclasses.
original
gif.php


<?php

Hey, thanks for the input.

I found a solution a while ago.


if (isset($filter))
{

imagepng($image);

Long time no see here.

I've made the emoticons as was suggested before! :D

The user control panel for the full size JustShout! is now up and running.

An example of some standard and custom...

Hey folks, yet again.




if ($back == "m") //$back is a value pulled from a db; that works perfectly.
{
$wid = $rowing['width'];
$hei = $rowing['height'];
...

As far as I know, PayPal use CGI, but you've a three way bet on CGI, Perl and PHP. Any guess is as good as any

Yeah. XSS! Some how they found an exploit in the posting of blogs on a user's site in which they use the HTML <!-- Comments --> <!-- Traffic Statistics --> Exploitary code here <!-- End Traffic...

Humm.....

Could you give me the structure of the table in your database?

Like

id INT Auto_Increment
dispname (VARCHAR)

or whatever it may be? That way I can have a play in my own db.

It's so called "script injection".

Are you using Wordpress blogs or WP-Stats in your website? For they are particularly vunerable?.The way that is done is with specially crafted SQL using certain...

I see, that makes a bit more sense now. So 11 could be K or something.. Well, I think your search is working perfectly (that I know of) but you're using LIKE %$trimmed%

Let's say that $trimmed is...

I don't really understand the question here. What is the difference between A11 and Id=11?

Sam

If it goes when .htaccess goes then the problem is with .htaccess.

Post us what you have in .htaccess and we'll tell you of any errors.

Yeah, there's most likely an error in the .htaccess file which is causing the problem; .htaccess is one of the first files the browser reads.

Don't know why you would because jpg is a lot worse quality than png. If I were you convert to gif, but that's just me.

Convert to jpg:


$image = ImageCreateFromPNG("yourimage.png");
...

Hey folks,

I have made an image-based shoutbox and now users can view older and newer message on the shoutbox depending on the $_GET['page'] - pagination - that works. However, since it's image...

If you opened said first process with

proc_open() then you can use the function proc_close() to stop it running again.

There's no way of hiding it completely but do you mean like this: instead of having http://www.daniweb.com/forums/newreply.php?do=newreply&p=618933 you just have http:/www.daniweb.com/forums - no...

Hi folks,

I have an image based shoutbox which I am currently implementing emoticons onto. I have a way now for the emoticons to appear where the :D or =) etc. is on the image, but for some reason...

Hi folks,

I have a system for an auctioneer and have on the form I have the fields: lot (the item), reserve price ([Reserve]) and minimum successful bid so far ([Min]). There is then a text box...

Yeah, I'm working on this but it's not as easy as I once thought, since it's image based so dynamic, not sure how I'd get the x/y values on the image for where the text 'xD' or '=D' or ':)' is. I'm...

Hi folks,

I have made a ledger sub in Excel. The task is to create a spreadsheet solution for a foreign exchange bureau so each transaction that happens it adds the details to a ledger sheet.
...

using your data, assuming 'tom', 'ron', 'chris' and 'bert' are table names.


DELETE tom.*, ron.*, chris.*, bert.*
FROM tom, ron, chris, bert
WHERE id = '$value';


Sam

' can be inside " and " can be inside ', but ' can't be inside ' just like " can't be inside ", but \' and \" can be used to escape the quotes so they are a character in the string, rather than the...

Cool, glad I could help! Perhaps change the last

"Success!! Blog failed!" To "Error!! Blog failed!"

Ok, try this


if(isset($_POST['submitbutton'])) {
$pass = mysql_real_escape_string(htmlspecialchars($_POST['password']));

$sql_a = "SELECT * FROM secure WHERE password = '$pass' LIMIT 0, 1";...

if(isset($_POST['submitbutton'])) {
$pass = mysql_real_escape_string(htmlspecialchars($_POST['password']));

$sql_a = "SELECT * FROM secure WHERE password = '$pass' LIMIT 1"; // change field and...

Hmm.. I'm not entirely sure, except you don't have <html><head><title></title></head>or<body></body></html> tags anywhere, which could cause a problem in your browser if you try to just post a <form>...

Also, assuming that there is a unique ID field there is an easier way. You can simply do a query like this:


SELECT *
FROM `tblxdetails`
ORDER BY `id` DESC
LIMIT 1 ;


and it will give you...

Once you have stored the password in the database there are two options:


$pass = mysql_real_escape_string(htmlspecialchars($_POST['password']));

$sql_a = "SELECT * FROM secure WHERE password...

How do you mean "can't get it to work"? What doesn't work? Do you get errors?

Add this to the top of your code


error_reporting(E_ALL);

ini_set('display_errors', true);

Try


if (isset($_POST['submit'])) {
$emal = htmlspecialchars($_POST['email']);
$name = htmlspecialchars($_POST['q']);
unset($error);

$error = array();
if ($emal == '') {

Glad I could help. =)

*mark as solved*

You used double quotes for the statement, but used them within, too.

so change your line 89 to this


$add_fax_sql = "INSERT INTO fax (`master_id`, `date_added`, `date_modified`,...

Ah, I see.

You closed your </a> before the Company Name.

So where you have


echo "Companytype :"."<a href= 'houseinfo.php?companytype=".$row["companytype"]."'></a>". "<br>";
echo...

Hi vijukumar,

You should make it so that the login form posts to the same page as with the login form $_SERVER['PHP_SELF'];

Upon successful login you should have it show a link for the user to...

Do you just want the link to open in a new window? (new tab in newer browsers) Or are you wanting a 'pop-up box'?

Sam

<?php
echo "<select name='dropdown' id='dropdown'>";


$sql = "SELECT country FROM tbl_user WHERE username='$username'";
$result = mysql_query($sql) or die("Error in sql: ".mysql_error());
...

<a href="javascript:history.back(-1);">Previous Page</a>


is an option.

Then if you're using php you could start a session $_SESSION['page'], with the page name set differently on each page....

Yeah, replace


addslashes($_POST['username'];


with


mysql_real_escape_string($_POST['username'];

There's something wrong with your connecting to the database then..


$connection = mysql_connect($dbhost, $dbusername, $dbpassword);
$db = mysql_select_db($dbname);


make sure you've spelt...