You can only access an object if it was declared in the same scope or an enclosing scope. That's the techno babble explanation. :) What it means is that if you declare something inside a loop, you...

You write a C callable wrapper that runs the method.

#include <cstring>
#include <sstream>
#include <string>
#include <vector>

using namespace std;

class Split {

I don't know. It looks like CreateRawDataBUFR is corrupting your object, but you didn't post the logic for CreateRawDataBUFR. Without the code I can't even guess where you went wrong.

system is in stdlib.h, not stdio.h. It's not a good idea either because now you depend on an outside program that might be malicious. It's a big security no-no because you created a hole that hackers...

Doesn't printing \n do the same thing as fflush?

The window gets destroyed when the program ends. If you call getchar so that it blocks for input, the program doesn't end and the window isn't destroyed until getchar returns.

All of the memory for the stack is preallocated. The OS allocates it when the program starts and frees it when the program ends, but while the program is running, it's all still there. Going in and...

No, it doesn't. But you _do_ lose the only reference to the space you had, and that's called a memory leak because now it's allocated and won't be freed until the program ends. If your OS doesn't...

You need to include stdlib.h. The error cryptically tells you that malloc wasn't declared and the compiler just assumes it's a function that returns int and casting from int to char* isn't friendly.

Try dividing by 10 until the number as an int equals 0.

float temp = net_pay[i];

while ( (int)temp > 0 ) {
temp /= 10;
}

printf( "Before the radix -- %f\n", (float)(int)net_pay[i] );...

I read about a trick that makes everything together. Move the PreDefStruct member to be last, make it an array of 1, and then make the APISTRUCT variable dynamic. If you allocate the size of...

Does this work for you?

#include <stdio.h>

typedef struct tagPredefinedStruct{
int iSize;
int iCount;
} PREDEFINEDSTRUCT;

typedef struct APIStruct {

Check the pointer to see if it's 0. If it is then malloc failed to allocate the memory.


You can't. Array sizes have to be constant and they can't be changed. A variable sized array is what I...

You can't set the size of an array at run time. You have to dynamically create the array from a pointer.

typedef struct tagPredefinedStruct{
int iSize;
int iCount;
} PREDEFINEDSTRUCT;...