Exactly, like I said. You would have one file say image.php generate the image and in the file you wanted to show the image you'd do

<img src="image.php?someparam=somevalue" />

If you want to place it dynamically inside another page you would have one PHP file generate the image and then point to that in an <img> tag.

But to set the content-type just use:...

What he said, it's been a long day :)

Remove [] from the name of the field, PHP sees that and tries to turn it into an array.

time BETWEEN '$endDateTime' AND '$startDateTime' Put quotes around the dates

Your first place you should go for any question related to PHP is the PHP documentation: http://php.net/for

What do you mean by calling the table? Also, why're you using PDO for the connection then just completely ignoring it and using mysql_query anyway? http://php.net/pdo

If you see absolutely nothing then you may be getting an error. On the line before $source = ... put ini_set('display_errors', 'On'); error_reporting(E_ALL); If you're getting an error that will show...

If the file is on the same server as the script then use the absolute path. If it's a remote file use the URL.

You're not giving a full path, you're giving a web path. In the first example it is making a web request to fetch the file, in the second example it is directly accessing the filesystem. Make sure...

If you want to save simulations for future use just use a damn database. Don't try to go against the grain when working with PHP. There are plenty of tools as your disposal for working with stuff...

You can't, use a database. It's that simple.

As for this, if you're just using it as a learning experience then it should be just that. It's not a very good learning experience if you just follow someone else's tutorial. The point of recreating...

If you're trying to get the value of $id in that string then you have to concatenate because you're using single quotes.

echo '<a href="profile.php?id=' . $id . '">Enzo's Profile</a>';

Now do the same thing, type php -v and paste the output here. If it says something like
PHP 5.2.6 (cli) (built: sometime)
Copyright (c) 1997-2009 The PHP Group
Zend Engine blah blah
Then you have...

oh, hahaha, did you also do sudo apt-get install php5-cli?

type php -v on the command line and paste the output here.

type ls /usr/local/bin and if php isn't in that list then reinstall it.

It's #!/usr/bin/env php and if that doesn't work then you didn't install php correctly. If you're using ubuntu or any debian distro it is just sudo apt-get install php5.

This will find the php interpreter for you and use it, don't directly link to it.

#!/usr/bin/env php

That won't actually get you the value of the hiddenName element though. You would have to do document.getElementById('submittedName').value. But since you're not really setting the value anyway you...

http://php.net/simplexml

If you get no errors and no exception is through but it's still a white page that means the query returned no results. Execute the query directly in MySQL or phpmyadmin or whatever you're using to...

Holy crap no. Just no. A thousand times no.

<script type="text/javascript">
function submitForm(val)
{
document.getElementById('submitted').value = val;
document.getElementById('submitted').form.submit();
}
</script>
<form...

http://php.net/preg_match That is all

What's the error? (also, your code doesn't have an ending brace for the outer if)

Your query might be failing


$result = mysql_query($sql);
Try

$result = mysql_query($sql);
if (!$result)
{
echo mysql_error();

Line 49

if ($_POST["$submit"])
// should be
if (isset($_POST['submit']))

The server it is working on probably has notices turned off. You should have an if (isset($_POST['username'])) block around that anyway.

heh, you can't exactly test load balancing with a ping and I can say without a doubt that if you DoS a hosting company to "test their load balancing" they'll be very quick to send a nicely formatted...

Show us your current code, we don't know you database schema or what to change if you don't

Explode on spaces and use ORs for the extra terms. http://php.net/explode

<?php
// create short variable names
$searchtype=$_POST['searchtype'];
$searchterm=trim($_POST['searchterm']);
if (!$searchtype || !$searchterm) {
echo 'You have not entered search details.';...

Well you have an unclosed/broken tag here on line 62 that may be causing issues

<div <!--Div class added by Damion -->

Aside from that grab firebug(http://getfirebug.com) for firefox and toy...

Is there some absolutely halting reason that the joomla stuff can't be hosted on the same server? It's not like its that hard to port a database and rsync code

Don't try to mix creating your own json strings

$objJSON = array('sample' => null);
// whatever
$objJSON['sample'] = $arr;
$objJSON = json_encode($objJSON);
echo '<script...

The problem is that get_browser returns an array, not an object. use $b['parent'], not $b->parent

Your example should work the way you want it. There is no dimensioning of arrays in PHP, space is allocated as necessary.

You use . to concatenate so echo ucwords($_SESSION['fname'] . ' ' . $_SESSION['lname']);