without glob module, just search for it

import os
os.chdir("/somewhere")
for files in os.listdir("."):
if not "_ab" in files:
print files

why do you think that regular expression is the way to go?

>>> s1 =' 25000 '
>>> s1.replace(" ","")
'25000'
>>> s2 = ' 5.5910 '
>>> s2.replace(" ","")
'5.5910'
...

it would be better to show a sample input file, your expected output as well.
to search in a file. just an example...considering i don't know what your file structure is like.

for line in...

another way

>>> for i in range(len(sentence.split()),0,-1):
... print sentence.split()[i-1],

try not to use input(). Use the raw_input() instead. (Its documented in the docs)

one method i always use is the os.path.join() method.

dir = os.path.join("C:\\","documents and settings","user","desktop")
starcraftpath = os.path.join(dir,"starcraft.exe")

takes care of the...

Personally, i would use a loop for this.

num = 32
b1 = 10
b2 = 2
x = 1
while 1:
if num%(b2**x) < num:
x = x + 1
continue

if you have Python 2.4 or above,

>>> import operator
>>> serial = 12345
>>> total=[[serial,'john'],[serial,'james']]
>>> sorted(total, key=operator.itemgetter(1))
[[12345, 'james'], [12345,...

if you just want to print to one output file, just do a redirect on your command prompt. eg


python yourscript.py > outfile

just use the for loop to go over each item, then manipulate from there

>>> for i in alist:
... print ' '.join(map(str,i))
...
2934110 B1 D4 7C7C7C7C804040404040F140404000
2934110 5 1 1 01...

if in the file, the content is indeed this:

[1,2,3,4]

then when you read the file line by line, you can use eval() to turn it into a list

for line in open("file"):
alist = eval(line)
...

is this what you are looking for

>>> s = "this is a string"
>>> alist = list(s)
>>> alist
['t', 'h', 'i', 's', ' ', 'i', 's', ' ', 'a', ' ', 's', 't', 'r', 'i', 'n', 'g']
>>>

import shutil,glob,os
os.chdir("wherefileis")
for FILE in glob.glob("journal*"):
shutil.copy(FILE, "someotherdir")

it's up to you. however its good to modularize so main() is definitely good to have.

you can use splitext from os module

import os,shutil
def renamer(target) :
os.chdir(target)
for filename in os.listdir('.') :
print filename
newfilename =...

its like this "\r\n" in DOS.

OP wants to collect IP address of browser. So guess he may be using CGI. here's an example (http://www.shindich.com/sources/cgi/clientip/clientip.py)

'0x' always appears in front, so if you want to use hex() and get rid of 0x, use hex(255)[2:]

maybe you can try this . Not tested


def invisible():
key = ''
passwd = ''
max_char = 8
while 1 :
key = msvcrt.getch()
if key == '\r': break

if you have pygame, you can use its inbuilt cdrom commands

import pygame.cdrom as cdrom
cdrom.init()
cd = cdrom.CD(0) # 0 = first cdrom device
cd.init()
cd.eject()
cd.quit()
cdrom.quit()

you can use the getpass module.

import getpass
pswd = getpass.getpass("enter password: ")
print pwd

a newline is represented as "\n", not "/n". maybe a typo error

from where did you get this command ?

Sincef you are new to python, i suggest you take the tutorial here (http://www.python.org/doc/).

split will break if your input have punctuations. eg word.Test . This will be counted as 1?
(although a blank space comes after a full stop.)
anyway, here's another way to do it,

>>> import re...

s = "open sesame"
print s[0:s.index('n')] + s[ s.index('n') +1 : ]

For your particular example, you can convert your list to a string, then find 'a'

>>> a = [(' ', ' ', [('a', 'Scott'), ('9', 'vth')]), (' ', ' ', [('a', 'Jenny'), ('9', 'vth')])]
>>> b = str(a)...

there are some cookbook recipe in ASPN you can refer to.
here (http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/82102).
they may not be wat you want, but at least will give you a head start

you should read the docs more. also googling with "Python word count" will show you some links to what you are looking for.

[] means an empty list in python.

you can read in line by line

for line in open("file"):
if "word" in line:
do_something(line)


you can read in one whole chunk

data = open("file").read()

there are several ways.
1) reading with for loop

o = open("output","a") #open for append
for line in open("file"):
line = line.replace("someword","newword")
o.write(line + "\n") ...

sys.exit() implements SystemExit, see
http://docs.python.org/lib/module-sys.html

Or you could do this

import operator
a = (1,2,3,4)
b = (4,3,2,1)
print sum(map(operator.mul,a,b))

Do you want to include decimals like 2.0 , 2.00000 etc as a whole number ??

Most string manipulation problems can be solved with Python's string functions. Only very complex ones will need regexp. So try not to use regexp if possible. Of course if you are good at it , then...

you need to put a decimal before doing the division:

>>> 6.0/4
1.5
>>> 6/4.0
1.5


or you can import future:

hi, wow, getter harder.:-)
anyway, here's a rather crude way and i am sure there are better ways (using re). I did substitution first, then do the rest

>>> data_raw = """
... header
... [23 ]...

sorry somehow i can't find my edit button, but anyway
a decimal/float looks like this : 245.332 or 4.5 or 74.32
so to match them, we need one or more digits, followed by "." and followed by one or...

another way is to use the "|" special character.

>>> re.findall(r'\d+\.\d+|\d+',data_raw)
['20', '35', '40', '84', '100', '245.99']
>>>