date -u causes UTC date/time to be displayed - FYI.

If you format date like this:
today=$(date +%Y%m%d)
you get a value like 20080111, this is a number - an integer.

When you split the input...

http://www.freebsd.org/cgi/man.cgi?query=sysexits&apropos=0&sektion=0&manpath=FreeBSD+4.3-RELEASE&format=html

for i in $(cut -f 1,3 -d: /etc/passwd)
do
echo "${i#*:}" "${i%:*}"
done


This lets you see what is going on. ${i#*:} is parameter substitution- returns the value just before the colon -...

try:

#!/bin/ksh

export infile=filename
filedate()
{
perl -e '
use Time::Local;
$mytime = timelocal(0,$ARGV[4],$ARGV[3],$ARGV[1],

You have to use either ksh (zsh) or bash to do this - ie., a modern shell with pattern matching.

cd /path/to/files
find . -name '*.err' |\
while read file
do
tmp=${file%%.das*}
mv $file...

try:

#
find $1 -type f -exec grep -l -e '/*' -e '//' {} \; |
while read file
do
grep -q ';' $file
if [[ $? -ne 0 ]] ; then
echo $file | grep -q -e '\.c$' -e '\.h$'...

sed 'n;s/$/;/' filename > newfilename

You need to use sed, and you have to learn about regular expressions.
based on your data a very specific (not generalized) solution is:

$> echo "Here's some text and ~this bit gets removed~,...

This will generate a report like you asked for.

nawk '
{ shortcode[$11]=$11
causecode[$12]=$12
result[$11 $12]++
}
END{ for( short in shortcode)
{...

It looks like you're trying to automate vi.

There are such things as "ed scripts" - scripts that invoke the ed editor.
You can use that scripting language easily. vi presents problems because it...

Why loop? you only need two rsh lines. You gain nothing by looping.

script:

# $1 = path to examine
# usage
# myscript /path

find "$1" -type d -print |\
while read file
do
permissions=$(ls -l $file | awk '{print $1}')

for i in vs01a vs01b
do
for k in 1 2
do
rsh $i echo $(tail -20 /opt/oracle/admin/+ASM/bdump/alert_+ASM"$k".log) >> VS_logs.txt
done
done

For "rsh" do you mean rexec or remsh? Or...

su or sudo

Read the man page for su.

Both of these require superuser (root) access.

The short answer is "yes". If you give an example of the data then we can help you.

The way disk i/o in unix works is that data is parked in an in-memory cache in the kernel - it is not guaranteed to be written to disk when the write() system call is invoked. Every 30 seconds or...

Record truncation? Not normal behavior unless the record has embedded ascii nul characters. Lack of disk space or exceeding enabled quotas will also cause the output file to truncate.

grep has a...

file_name=`echo "$file_name" | sed 's/ //g'`


That removes any spaces in the file_name variable

find does date comparisons for you.
Example - this code deletes files older than 48 hours (2 days):

find /home/julie/trash -type f -mtime +2 -exec rm -f {} \;

myvar="Hi there"
backwards=`echo "$myvar" | rev`
echo "$backwards"

One way

grep '^TDR ' Inputfile.log

awk is what you want.

Assume your extract code runs like this: extract
and it prints data to stdout.

And assume you have columns of data and you want column #3 to be larger than 10.

...

If you don't want the user to notice the script running:

nohup script.sh <parameters> 2>&1 > ./logfile &


As long as your script does not ask for user input this will work. Otherwise you...

while read text
do
echo "$text" | sed 's#[|:;>]# #g' | read nm1 nm2 nm3 nm4
echo "$nm1 $nm2 $nm3 $nm4"
done < inputfile

echo 'ftp://user:pass@host/path' | sed 's#[|:;>@/]# #g' | read dummy usr pwd hst pth
# or
echo 'ftp://user:pass@host/path' | tr -s '/' ' ' | tr -s ':' ' ' | tr -s '@' ' ' | read dummy usr pwd hst...

Since the homework deadline has gone by and somebody may search.

One simple way with sed

# using sed for wc -l
sed -n '$=' filename

Another option: grep.

You have to show effort before we do your homework for you.

There is also a sed one hunk of code that does it as well.

You can also use a while ... do .. done loop.

Since this is in Shell scripting:

pid=$$

$$ returns the pid of the current process (the one the shell is running in)

This is actually an Oracle question:
dba_profiles sets the rules for the system, not how many login failures there are for a given user.

Offhand I do not know what SYS table Oracle currently uses...

I changed it so awk puts it all on the same line.

I'd use arrays:

#!/bin/ksh
optfile=filename
set -A opts $(awk 'BEGIN {FS="="} { if($0~ / page_size/) { print $2}}' $optfile)
for i in 0 1 2
do
echo ${opts[i]}
done

#!/bin/bash
# we want to copy from path1 to path2
# step 1 make all the subdirectories
find /path1 -type d | \
while read dir
do
mkdir /path2"${dir#/path1}"
done
# step 2 cp the files...

This checks $2 to see if ".kext" is anywhere in the $2 parameter

echo "$2" | grep -q '.kext'
if [[ $? -eq 0 ]] ; then
echo '.kext found'
else
echo '.kext not found'
fi

In that case you have to use cp. mv does not mv over mount points.

awk works for this pretty well -

awk '{
print $0
if($0=="Line2") {print "INSERTLINE2"}
if($0=="Line3") {print "INSERTLINE3"}
}' file > newfile

Use

mailx -r '<from name>' -s '<subject here>' john@somewhere.com < message_text_file

cd /to/my/directory
find . -name '*.jpg' | \
while read file
do
mv $file "new"$file
done
PS: mv works only within a filesystem. Even though you may be
in directories that are close in...

find syntax is wrong there has to be a path
find PATH -name

In your case it looks like you should use a . (a dot ) which means the
current working directory.

#!/bin/ksh
find /path/to/files -name 'tmp_*' | \
while read filename
do
tmpfile=${filename#tmp_}
mv "$filename" "emkt""$tmpfile"
done

try an alias:

alias home="cd /home/budroeducom"
alias cd1="cd /some/longpath/to/somewhere"

typing

home

will execute