Standard C doesn't allow you to declare variables in the middle of statement blocks.

Post your code!
Did you initialise i ?

result[numchars++] = basechars[r];

When you're done, print from numchars-1 back down to 0 (one char at a time).

> basechars[r]
You're printing them, not storing them!

Store each char in another array, then print it out backwards?

Well it's good for bases < 10

char basechars[] = "0123456789";

and
printf("%c", basechars[r] );

> That is how I get the binary.
That's how you do it for every other base as well.

How would I know.
You've now got two programs, and you've posted the code for neither of them.

if(! CreateProcess("C:\\WINDOWS\\system32\\cmd.exe",
This needs to be something like
if(! CreateProcess("C:\\Users\\me\\Documents\\Projects\\Fib\\myfib.exe",

It does all the work.

This code...

Use %s to print a string of chars.

> if(fgets(temp, sizeof(temp), file) != NULL)
To read the whole file, do
while(fgets(temp, sizeof(temp), file) != NULL)

Oh, and remove the fclose() from inside the loop.

Or better yet, leave...

You can't assign arrays.
Use strcpy() instead.

It would be better if you actually posted your actual error message.

Rather than saying "an error", hoping we can be
a) bothered to run your code
b) actually end up with the same error message...

> Try this..Does it do your job:
Well it might, if you included stdlib.h as well.

Then you might be able to call malloc without having to resort to dangerous casting (it's REALLY dangerous...

To further what Tom Gunn said, if you changed
char name[25]

to
char *name;


then the second printf would immediately be very wrong indeed, and not just ever so slightly odd.

> "program to swap two no. using third variable"
A better question would be:
"How to swap my idiot teacher of 1970's assembler tricks with someone who has a clue about programming in the modern...

> I am trying to work learn thread programming in C.
Mmm-kay,

> I have my turbo C installed and its working fine.
You're stuck then.

> Please do shed some light on how to configure my Turbo C...

Use fgets() to read each line.
Use sscanf() to parse the line (or better yet, strtod).

> saveToFile(*client_file, *cd);
Neither client_file or cd are initialised.

Something like this

client_file = fopen("data.txt","w");
if ( client_file != NULL ) {
saveToFile(*client_file,...

One function to write the struct to a file.
Another function to read the struct from a file.

For each field, use the appropriate fprintf or fscanf conversion function.

For extra robustness on...

> This is just a skeleton.
In other words, a complete waste of time.

Post an accurate facsimile of your actual problem, and you might get some useful answers.

Post random dribble in a...

> void processone(int delay);
This is an int

> processone(av[1]);
This is a char*

> void processone(char avinput)
This is a char

Making prototype AND definition a char* as well would go a...

Post some more code, for example all the other declarations of variables used in this code.

You need to post some context.

What is error 468, (I've no idea, each compiler is different).

Which line is that on?

Does it happen when you compile the program or run it?

Like so

#include <stdio.h>
#include <string.h>

struct student
{
char studName;
int studID;
char sex;

So what is your question?

> vararray[v+1]==NULL
Well if vararray is an array of char, then testing the nul character (as opposed to the NULL pointer) is what you should be doing.

As in
vararray[v+1]=='\0'

insert() returns a value, which you're ignoring.

Yes, it's OLD C, and it defaults to int.

Oh yeah!
http://www.daniweb.com/forums/thread210533.html

http://www.daniweb.com/forums/announcement118-2.html

You only enter a string, not a number.

Typing in 123
will likely get you
49 50 51
as output.

If you were expecting 123 to be printed, you need more code.
At the moment, you just print the...

Also consider the lack of usefulness of a string containing only one char (a \0)

It's a nice idea.
But there are at least 6 places where code tags are mentioned, and still about 99% of noobs fail to use them on the first post. People get +ve rep just for proving they can read -...

There's no such thing as an "array of bits" in C.

http://clusty.com/search?query=sha1+source+code&sourceid=Mozilla-search

You don't increment the dest array pointer.
The destination isn't big enough.

A short guide to const.

char a;
const char b;
char *p = &a;
const char *q = &b;
char * const r = &a;
const char * const s = &b;

Step 1, read right to left, so for example

You seem to have figured it out - what do you want me to suggest?

http://c-faq.com/malloc/index.html

* Memory leak
Calling malloc() without calling free().

* Buffer OverFlow
Accesses outside the bounds of your memory. Can equally apply to arrays as...