you are adding counter twice in your loop, need to remove one.
void primeTest(int n)
{
int temp = 2;

for (int counter=1; counter<=n; counter++)
{
cout << "Prime number " <<...

It might be that you are linking with some dll's that aint in the folder you are executing from or in the system folder. try to look at the propeties for the project in VC and see if they link to...

Words are generaly seperated by spaces, so look for spaces between charaters.

>He said "factorial," zyruz.
My bad :)
you can also use a while loop:

#include <iostream>

using namespace std;

int main ()
{

you can do somthing like this:


#include <iostream>

using namespace std;

int main()
{
int num = 50; // test num

becuse you are writing to the file after you are done with the loop. so put

file<< i <<" "<< j1 <<"\n" ;
inside the loop

file<<"%d file\n",rand();

cant be dont this way, it is not printf() that you are using :)
try:

file << rand() << " file\n";

>Ok But how can i get the value of the 5th element? does cout<<a[5]; will do?

well,it will ouput the 6'th element, since arrays start on 0.

>And what if i want to output all the elements? do I...

You can do somthing like this:

#include <iostream>
using namespace std;
int main()
{
char test[] = "1234567890abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ.!:;? ";// all the chars...

becuse you dont use CODE tags.
http://www.daniweb.com/techtalkforums/announcement8-3.html

try to use a filname without space :)
it worked for me then

well it is kinda har to guess wath you want for req's when I have no idea wath max req's and sutch are, so I'l just poste some name:

Weapons:
Hammer of Thor (pref do some extra lightning dam :) )...

tried using wchar_t instead of char?

if you are trying wath I think you are you need to change
struct Output
{
double *var1;
double *var2;
double *var3;
}
to

struct Output

for(int i = 0; i < 512; i++)
{
output[i].var1 = (double *)i;
output[i].var2 = (double *)i;
output[i].var3 = (double *)i;
}

shuld populate it.

I have taken a closer look on your code, and think I see wher your error is.
y = x/150*(log(pl/1.5));
and
y = x/(150*(log(pl/1.5)));
are 2 completly diferent calculation. this might be your...

log(x) ; returns the natural log of x, accept it.
Are you sure that you are thinking of log?
can you give us a couple of examples of wath you want to be done?
Guessing wath you want is hard.
...

you can do it that way, but yo loose alot of readability!

log(x) is the natural logarithm of x (base e)
log10(x) is the common logarithm of x (base 10)

the probleme is that you have declared log as a float. and a float is not a function and a float variable cant be used as a function.
so ether change (150*log(pl/1.5)); to (150*std::log(pl/1.5));...

From http://www.daniweb.com/techtalkforums/showthread.php?t=27800


use <iostreram> instead of <iostreram.h>

Dont try to print out a void function.
change cout << Backward(line) << endl;
to
[CODE]
Backward(line);
cout << endl;
[CODE]

make the key 1d?
like:
char key[20]= {'B', 'D','A','A','C','A','B','A','C','D','B','C','D','A','D','C','B', 'B','D','A'};

remove : "change answer[quest-1] = choice;" and put:

if (choise ==...

why do you need to have this as a 2d array?
if you just want the numbers 1-20, you can change the function StudentAns to:

void StudentAns(char answer[20])
{
for (int quest = 1; quest <=20;...

You can do it like this:

#include <iostream>
struct alphab
{
int num;
char ch;
};

int main()

If I aint totaly wrong Dave ment somthing like this:

char ch[] = "abcdefghijklmnopqrstuvwxyz"; // character array
char testc = 'c'; // wath we are looking for
int res = -1;
for...

small tips:#include <iostream.h> is old style, use <iostream>, and main shuld return int (int main).

Ok, I dont know if you have loearnt about vectors, but if so, they wold be a better choise for...

Well you have newer declared i, before refering to it in if(!count[i] % 2) // if divisible by 2, then returns zero, negates to 1, enters if
even[i] = count[i];
else
odd[i] = count[i];

just so...

I only recommanded that he used function, the system("pause ") was only becuse mixsir used it in his code.

It is printing the number multiple times, becuse of:

for ( int j = 2; j <= i/2; j++)
{
if ( i % j == 0 )
{
check_prime = 0;
...

somthing like this:

#include <iostream>

int main ()
{
char c[6] = "45678";
int num[5];
for (int i = 0; i < 5; i++)
{

it show the menu 1,2 and 3 becuse in if (myDifficulty = 3) you aint checking, you are asigning the value 3 to myDifficulty change it to if (myDifficulty == 3)

no match for 'operator>>' in 'std::cin >> myDifficulty' is the error I get, and it means that you havent declared anny overload for the >>. but use int for geting the choise, and use the enum for...

Your probleme lies in if (myDifficulty = 3)
You are only asigning the value 3 (or 1 or 2) to the myDiffculty, change the '=' too '==' and it shuld work.

You arent using the enum difficulty.......

Your main probleme is that you have bad design. Try to figure out how to do somthing before you try to code it :).
But, I rewritten your code:

#include <iostream> // use <iostream> instead for...

If I aint completly wrong you need to include fstream.

Well, it cold be that dave, but he is using cin.ignore(std::cin.rdbuf()->in_avail() + 2); as a system("pause"); and there can be code afterthe pause, and then it would be a bug.

just change the
cin.ignore(std::cin.rdbuf()->in_avail() + 1);
to
cin.ignore(std::cin.rdbuf()->in_avail() + 2);

Well for me it seems that he is trying to reinvent the wheel for a school projeckt, and not use standar function.

desidude: try somthing like this:

std::string Hex(int num)
{
std::string s1;
char sign[] = {'0','1','2','3','4','5','6','7','8','9','a','b','c','d','e','f'};
int div,
...