That doesn't make much sense. What you said(IF you said what I think you said) can be achieved more conveniently using a loop.

Use int main(), indent your code, use switch cases and a while loop instead of goto and if cases.

Daniweb isn't a program spewing machine that you can command.

Here's a useful link (http://www.java2s.com/Code/C/Development/Howtochecktheperformancedifftime.htm)

This is wrong:
for(i = 0; i < n; i++){
for(j = 0; j < n; j++) printf(" %d", MatrixMult( a, b, c, &n ));
printf("\n");
}

You can't return arrays since they are always passed by...

Better use fscanf() to read integers. If you use fgetc(), you'll be reading the ascii values of the integers and not their actual values. Also every digit will be treated as a character. How will you...

That's quite a complex piece of code you got there. Since I'm still a beginner it took me quite a while to understand it's logic. I'm just surprised that you could come up with that logic and not be...

Hmm. I guess I misjudged the working of fgetc(stdin). Will look that up.

It usually happens if the string isn't NULL terminated. It would be easier to figure out your problem if you posted your code.

Also, in my previous code, you'll have to flush the input before...

This is all you have to do to prompt the user till he enters a string with a period:

char msg[50];
int length = 0;
do
{
printf("Enter a string and end it with a period\n");...

Correct way of using code tags:


.
.
Your code here
.
.

Appending a new employee to the should be easy. Declare a few "templates"(poor choice of word, perhaps) of string such as:


char empInfoTemp[] = "Employee ";
char nameTemp[]= " Name : ";
.
....

You declare it as an integer.
Ex:
int hex = 0xBCD;
printf("%x",hex);

MNTABPTR is only a pointer whose size is 4 bytes(32-bit system). What you want is to allocate memory for the size of the structure MNT which is 132 bytes. For which you either do this:

newnode =...

/* Allocate one item of the type p points to */
p = malloc ( sizeof *p );

That's looks like a really neat way of allocating memory, and I can see how it can be less error-prone. Thanks!

malloc() always returns a void pointer. You need to typecast it. students = (struct student**)malloc(sizeof(struct student));

So your output is this:


*
***
*****
*******

No of starts: 1,3,5,7.

It might work this time if the C compiler you are using grows sympathetic towards your blind persistence.

That doesn't do any good.




Are you sure about the output?

1st row should have 1 asterisk, 2nd row should have 3, 3rd should have 4 and 4th row should have 6?

The upper limit of an int is 2147483647(32-bit system). When x reaches the value 1073741824, x<<1; multiples that value by 2 which yields 2147483648 which is beyond the upper limit, hence the value...

Do you want to do it just so you could justify it to the right? If so you could use this:
int i=444;
printf("%9d",i);
It won't include any zeroes at the beginning but it'll be right justified.

Well, that i knew. I guess i just misinterpreted your previous post. :)

I don't understand how that converts binary to decimal.

What's the significance of this piece of code?

for(i=0;i<8;i++){
if (input[i]!=48&&input[i]!=49){
...

scanf ("%[^\n]", string);
scanf("%c", &dump);

Yeah, the above code will take in whitespaces as well. Or you could use gets() or fgets() to be safe.Reason not to use gets...

You still haven't pointed out why you are passing a character array as an argument. And your result variable seems redundant too. And as Salem pointed out it can be done using %s in scanf()like this:...

scanf ("%d", &a);
a is declared as a float, so %d should be %f.

Function definition-
int mypower(float a, int n);
there's no semicolon at the end. (as Salem pointed out.)

int power
return...