'tmp' string might be null. put a check like this after you do the 'readLine' and try


if(tmp != null)
{
//your code
}

This thread here talks about float comparisons. There's a good link available in the thread about the same.

Thread1 (http://www.daniweb.com/forums/thread73810.html)

And who are 'they' ?? My opinion, C++ is way harder than Java, so don't start with wrong notions.

If you are compiling them one-by-one make sure you only compile and don't go to the linking process. I think you might be doing that and while trying to create an executable its not finding main....

1->atoi signature is this:

int atoi ( const char * str );

2-> read some more threads here to find out alternatives to atoi. You should avoid using it.

Before even going into your logic i have a couple of things I can tell you

1-> Read the code-tags page carefully and learn to use them correctly. it would make your code much easier to read.
2->...

There's a post at the top of the forum Read This before posting (http://www.daniweb.com/forums/thread78223.html). It talks about using code tags and posting well indented and easy to read code....

I would say you can use the following algorithm

1> convert both the arrays to all upper case or all lower case
2> sort both the arrays
3> compare the contents
4> at first mismatch print 'its...

where's the code for TestAccount.cpp?

point->item->return_value();should give a segementation fault.

i saw you 'Promosion::linkup' function and nowhere you are assigning anything to the 'Applicant *item;'. it will be NULL or may be...

for(i = 0 ; *Src!='\0' ; Src++)
tmp[i]=*Src;


should increment 'i' also. as of now 'i' remains 0 throughout.

or you could do something like ...

int* arr = new int[rows * cols];

then go on adding elements to it ...

i think its more because of the keyword 'virtual', just try and remove that and it compiles and excutes fine. Normally the class Second wil call the ctor of class First and then class First will call...

i dont think you should assign a char inside double quotes. Try

play[2] = '*'
if (play[2] == '*')

hex2bin[h] will give the value for the key 'h'.
i executed each statement separately, without declaring the dictionary and the output will make things very clear to you


>>number=1000
>>for h...

just print out the array using 2 for loops.

something like


int a[m][n];
cout << "Name" << " " << "Total" << endl;
for(int i=0;i<m;i++)
{
for(int j=0;j<n;j++)

Please use 'Code Tags', i dont know how many times the mods have been telling this.

secondly just pasting too much code is not going to help anyone, sometimes it can even confuse the person. It's...

i dont see anything wrong with the code above and when i executed this i got this output



edit: forgot to mention that the output is succesfully written to the file also. I hope you have the...

From your logic you didnt need an array of integers at all. you are writing the value to the same pointer every loop. if you want to use the array do something like this.

cin>>ptr[count]

and...

To me the usage of operator overloading to do this doesnt seem good.. you have a collect class and that has an array of movie class. simply write an addMovie function in collect class, pass on the...

when you declare a function as const, it implies that you cannot change the state of the object inside that function. that means you cannot change the value of any member variable inside the function...