you need to post a question if you want an answer.

when you 'getch' you're taking the next character off of the input queue for processing.

this assumes once you've processed it, you're done with it, and will (probably) eventually want to get...

the main() program can often be called by a parent program. 'return 0;' indicates to the caller (parent) that the main() program executed correctly.

so... generally speaking, the main function...

the error is probably due to the fact that 'x' isn't initialized, so it's value is something like negative eleventy thousand, causing your program to crap the bed when it uses it as one of the array...

you got both loops fighting over the same index 'i'

this thread is a disaster. :)

you are a patient man, Salem.


.

use code tags correctly. and make sure your code is indented. otherwise, it's a ridiculous mess, and no one will want to look at it.

int main(void)
{
// hello, i am properly formatted...

:$

yes, you're right.

even though it works for this trivial example, not casting it properly is a bad habit to get into.

the correct way to initialize it is:

char q[16];
char *p = (char...

try this:

char q[16];
char *p = &q;
strcpy(q,"abc");

.

this is no more "my" home than yours. do you see a "mod" bubble by my name? no. i don't even have a "featured" bubble, like you and serkan.

i just am blunt, and have little tolerance for...

hardly. because then who would i have to beat up on in geek's lounge?

:P

your post wasnt harsh. it was honest and insightful, and far more gentle than I'll ever be. Mine was harsh. and here's one that's harsher:

The problem is, Serkan is always coming around here...

there are plenty of people with more rep points than me who haven't been featured. and rep points are just as subjective and arbitrary as being selected to get a "featured poster" bubble. i mean,...

jesus shut up already. no one gives a flying shit that your best friends didnt get "featured."

this is not your thread to ask basic questions. go open your own thread on how to use IF.

and if you don't know how to use sscanf() -- much less how to look it up (http://lmgtfy.com/?q=sscanf)...

what you have written here is an identifier from a #define'd constant -- not a string.

if it were a string, then you could use sscanf() as Tom Gunn suggested. but he's assumed that you really...

your .NET installation is broken. Unless you're some sort of windows/.NET guru, the chance of you fixing it correctly is small.

uninstall all visual studio and .NET components, reboot, then...

$350 a lid?

holy shit, you kids these days.

:icon_rolleyes:

i made a mistake. i said the OP who suggested that programmers were stoners was from the u.s. midwest... that's not correct. Menster is apparently from Australia.

so let me make my own...

Yeah, and Hempfest is coming up soon. I wonder if Seattle's former Chief of Police, Norm Stamper, will be there speaking on behalf of marijuana legalization/reform.... again.

:D

this is a bizarre correlation that you've made, that most programmers are "stoners".

i don't really know many programmers who are "stoners". most of them are intellectual types (or even...

'k' is a pointer. meaning it describes, or "points to," an address of memory.

when you first declare this pointer, there is no memory allocated for it and the address that it points to is...

that's one way to do it. I prefer to use "strtol()", because you can do more robust error checking to see if the user entered a valid number.

but sure... try "atoi()" to get started.

.

fflush(stdin) is totally, utterly, and completely wrong.

never, ever, use it.

learn to parse your input correctly in the first place, and you wont have this problem.

so get rid of scanf()...

here's an early reply: get your PhD in post-hole digging.

i mean, jesus.

if you need an internet chat forum to tell you what your career research focus will be, you probably should go on...

most of these trifling problems will go away when you throw away the P.O.S. Borland/Turbo compiler and get a real C/C++ compiler like CodeBlocks (http://www.codeblocks.org) or Bloodshed Dev C++...

the answer to your basic problem:
if isdigit(cResponse);
is incorrect. it should be
if (isdigit(cResponse))
{
// do stuff here
}

(1) an if-statement must be entirely enclosed in...

or, conversely:

you post your code there, and wait for someone to make it better and hope some guy doesn't expect you to actually learn something, and you can just sit on your ass waiting for...

i dont know what you did, but your code is not visible.

so, please use code tags.


put your code here

^ i like that link.

i don't think there's an equation without using summation. i tried to think about it for a minute, but gave up. I'm not really a math guy. :D

it's just LaTeX markup tags. any reference will describe the basics

http://en.wikipedia.org/wiki/Math_markup

and you don't need a "Big Number Library". you dont even need a long int. 10,000 is easily represented by a regular integer

the way to approach this problem is by summation:
...

the formula posted by siddhant is fundamentally flawed. it only appeared to work, because it just happened to be valid for n=2 through n=8. as 'n' increases past 8, the result becomes more and...

^ self-deprecating humor only works if there's a clear distinction between the person and the parody.

in other words: when a creepy internet stalker jokes about being a creepy internet stalker,...

EDIT: never mind. find it yourself. (http://lmgtfy.com/?q=mulitple+precision+library)

I say that you should avoid the use of old, non-standard libraries like "conio.h" unless you are explicitly instructed -- required -- to do so.

anyone can quickly learn to use any library...

what salem said.

and, anyhow, if you really want to do this correctly, you will use the standard C library <time.h> (http://www.cplusplus.com/reference/clibrary/ctime/) ... you will make use of...

oh, hell, i just cut and pasted his code. i didn't even notice that

:)

um... you pretty much just described the two steps.

$ gcc file1.c main.c
$ ./a.out

what more do you want to do?