You have two loops


for (i=0; i<n-1; i++)
{
for (j=0; j<n-1-i; j++)
{


but I can't see where you initialise n. Try printing the value of n to the console just before that line and see...

Yes, but to make your code easier to follow it might be worth writing "else if (choice==2)"...

if (choice==1)
{
//HERE CHOICE = 1
for (i=0; i<20; i++)
{
cout<<"\n"<<num[i]<<endl;
}
return 0;
}
// HERE CHOICE STILL EQUALS 1!

http://gcc.gnu.org/ is the official site for the gcc compiler. Latest version was released in March this year and is version 4.3.0. Note that it is actually a standard compiler that is usually...

It seems as though you've done everything up until this point. For this section you need to:


somehow prompt the user for some coordinates
use these coordinates to form some lines
sum the...

Sorry dougy83, you are correct, and thanks for helping my understanding. :)

You write it like this:

int main()
{
int x, y;
cin >> x;
cin >> y;
if (x==0 && y==0)
// the && means and, use || for or
{

You use const in this situation because the strings aren't going to change, you want them to remain constant.

The char * is an object type in C++ that literally means "pointer to char". The char...

I haven't used a mac for quite some time so I could be wrong, but don't most macs come with g++ these days? You can use it from your Console utility and should be a sufficient compiler for a starter...

One advantage of lists that I can think of is that it is often easier to rearrange the data in a list because you are working with pointers. That is, if you have a list of objects and you want to...

I'm pretty sure this should work:

char c;
cin >> c;

I haven't tried it, but it only allows for a one character input I think...

The first parameter tells you how long the first row (I guess this is the base of your pascal triangle perhaps?) is. The second parameter tells you how many rows there are (the height of your pascal...

Hope this has helped,

darkagn

I'm sure there's a more elegant solution but you could create an array where each element is the result of an OR result of the other two arrays.

for (int i=0; i<10; i++) {
array[i] = a[i] ||...

A couple of comments for you to consider:


You will need a variable of type float or double to store and print the average
You can use modulo arithmetic to get the digits of a number (%)

...

Try something like:

int total = 0;
for (int i=0;i<10;i++) {
total = a[i]+b[i]+c[i]+d[i]+e[i];
// print result
printf("total = "+total+"\n");
// print i to see which iteration of the loop...

Sorry, I don't understand your question. Do you mean How do you select the same element from a series of arrays and add them together?

You have not declared your i before this line. An array needs its size set - you have done this correctly in your string array. You need to declare your i...

In this thread (http://www.daniweb.com/forums/thread89711.html) I explain a similar question by example. It sounds like you need to describe the time complexity of this code in terms of k but I'll...

The main difference between the while and do-while loops is that the condition in a while loop is checked before the inner code is executed, whereas the do-while loop's condition is checked after the...

I think you want hours as an int and minutes as a float.

First, you need to loop until the input = "E". The prompts would work like this:

int lineNumber = 1;
cout << lineNumber << "> ";
cin >> temp;

This will prompt with the current line number....

Sorry there Ken JS. I'm struggling to remember this stuff but I thought that the parity check matrix was generally binary. Because your G is not in binary, I don't think you can apply (mod 2) to it,...

I stand corrected - apologies.

Yes dougy83 that is what i was getting at, but I didn't want to give away the answer. :P

Minor point: don't forget that in C++ you must initialise your variable outside the for loop:
int e;
for...

The statement e=e%2; will result in e being equal to the remainder of the division of e by 2. In other words, if e is even, e will become 0, if e is odd, e will become 1, and e will not change after...

In binary, -1=1, so -P^t=P^t. What you have done looks good to me, but maybe someone else can check for you also? It's a long time since I did this sort of thing...

Hi Laseredd,

That short program looks good! I think you have shown understanding of some very important C++ principles here, classes, methods, I/O. :)
As an extension, how do you think you would...

Don't do that. It is much better programming practice to separate functions where possible. Imagine if you had to call int Add (int x, int y) ten times with different variables for parameters? Or a...