Someone will correct me on this if I'm wrong, but if the output for this is to go to the screen (I didn't think about what it was supposed to do until later) you'd be better using echo instead of...

That usually means a syntax error of some sort.

Isn't the format for the print 'function':
print ( a string );
(Note the brackets).

And you've not got a paired ' in the last one.

And...