it would be better to show a sample input file, your expected output as well.
to search in a file. just an example...considering i don't know what your file structure is like.

for line in...

another way

>>> for i in range(len(sentence.split()),0,-1):
... print sentence.split()[i-1],

Personally, i would use a loop for this.

num = 32
b1 = 10
b2 = 2
x = 1
while 1:
if num%(b2**x) < num:
x = x + 1
continue

it's up to you. however its good to modularize so main() is definitely good to have.

you can use splitext from os module

import os,shutil
def renamer(target) :
os.chdir(target)
for filename in os.listdir('.') :
print filename
newfilename =...

For your particular example, you can convert your list to a string, then find 'a'

>>> a = [(' ', ' ', [('a', 'Scott'), ('9', 'vth')]), (' ', ' ', [('a', 'Jenny'), ('9', 'vth')])]
>>> b = str(a)...

there are some cookbook recipe in ASPN you can refer to.
here (http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/82102).
they may not be wat you want, but at least will give you a head start

you should read the docs more. also googling with "Python word count" will show you some links to what you are looking for.

you can read in line by line

for line in open("file"):
if "word" in line:
do_something(line)


you can read in one whole chunk

data = open("file").read()

there are several ways.
1) reading with for loop

o = open("output","a") #open for append
for line in open("file"):
line = line.replace("someword","newword")
o.write(line + "\n") ...

Or you could do this

import operator
a = (1,2,3,4)
b = (4,3,2,1)
print sum(map(operator.mul,a,b))

Do you want to include decimals like 2.0 , 2.00000 etc as a whole number ??

Most string manipulation problems can be solved with Python's string functions. Only very complex ones will need regexp. So try not to use regexp if possible. Of course if you are good at it , then...

you need to put a decimal before doing the division:

>>> 6.0/4
1.5
>>> 6/4.0
1.5


or you can import future:

hi, wow, getter harder.:-)
anyway, here's a rather crude way and i am sure there are better ways (using re). I did substitution first, then do the rest

>>> data_raw = """
... header
... [23 ]...

sorry somehow i can't find my edit button, but anyway
a decimal/float looks like this : 245.332 or 4.5 or 74.32
so to match them, we need one or more digits, followed by "." and followed by one or...

another way is to use the "|" special character.

>>> re.findall(r'\d+\.\d+|\d+',data_raw)
['20', '35', '40', '84', '100', '245.99']
>>>

i think its answered in the other thread

hi there
sure, re.findall(r"(\d+)",data_raw)
thanks

assuming data is as first posted:

>>> import re
>>> re.findall(r"\[(.*)\]",data_raw)
['20 ', ' 35 ', '40 ', '84 ', '100 ', ' 245', ' 260', ' 300 ', ' 440 ', ' 521 ', ' 650 ']


...

can you try :


dates = [i for i in files for j in months if j in i ]

another way...but you have to test it in different cases...

lst = [11, 'Dick', 12, 'Mary', 7, 'Zoe', 9, 700, 777, 'Paul', 13456789]
slist = sorted(lst) #sort the list
min_num , max_str =...

what is your error, and what is your expected output/results?

if you don't want to change list1, you can do

list1dup = list1[:]
list3 = add_item(list1dup)
...

if you just want to find "Paul" in your example, one way to do it is to convert that list to string

astring = ','.join( str(i) for i in nested_list)
if "Paul in astring:
print "Found"

this is the problem

grade = input("Enter gradepoint for course (Enter to quit): ")


input() expects a number. when you just press enter, it gives error
maybe a try:except can solve the...

if your lists comparing only numbers, you can sort them first?

if sorted(li) == sorted(li2):
do something

def en_de_code(text,flag=0):
if flag == 0:
return ''.join([chr(ord(char) + 1) for char in text ]) #encode
else:
return ''.join([chr(ord(char) - 1)...

In Python docs first para here http://www.python.org/doc/2.4.1/lib/typesmapping.html

"""
2.3.8 Mapping Types -- classdict
A mapping object maps immutable values to arbitrary objects. Mappings...

do you want to comment out "import sys" and try again?

>>> a = []
>>> if a:
... print "not empty"
...
>>> b = ['a']
>>> if b:
... print "not empty"
...
not empty
>>>

hmm.list comprehension?


alpha = [ c for c in list if str(c).isalpha()]
number = [ c for c in list if str(c).isdigit()]


if you want to get unique elements, use set

if you look at the xrange() docs. it says "returns an ``xrange object'' instead of a list"
if you want to use xrange(). use a for loop

for i in xrange(1,5):.....

it's best if you could explain what you wish to do, give sample input and output if possible

''.join(['\xc7', 'g', '\xea'])

Does all the lines you want end in "BANK"?

I assume you are working on win32 platform
if you have the win32 module, there is an example demo called win32netdemo.py and inside the source, there is a function call ServerEnum(). You can take a...

....
dec = e.decode('string_escape').decode('utf8')
for i in dec: print ord(i),
...

you could try this:


>>> a = unichr(275).encode('utf8')
>>> b = a.decode('utf8')
>>> b
u'\u0113'
>>> ord(b)
275

thanks..yes i know.
I was giving an example on his first post.. doc and txt files. :)