Well I mean, it's not very fun even if I assumed it wasn't homework. When you take a coke, just pull the next one to the front.

This game sucks; do your own homework.

What unoriginal fluff. This wouldn't even be copyrightable. Why don't you come up with something new, something youthful and interesting, something unpredictable???//slash Do you have no spirit? ...

YOU DIDN'T POST A NUMBER!!!!

let polyeval x = foldl ((+) . (* x)) 0
in polyeval 10 [1,6,0,8]

Well I just thought that there was a good chance somebody had written 1562 before I hit submit.

11001000110

1563

No.

Have you met Alker Saltzo?

Yes.

Are you smarter than your friends?

No.

There exist nontrivial roots with real part not equal to 0.5 of the zeta function?

Yes. Edit: No.

Notation Polish reverse speak in you do?

Yes.

Are you me?

No.

Do you understand the instantiation of the concept of existence?

no.

Do you worship a zombie?

No. I prefer Vi. Not as clumsy or random as Emacs. An elegant text editor for a more civilized time.

Are you serious?

No

Are you answering no to this question?

Oh, 10 m/s^2. Thanks for pointing that out.

fork

spoon fied slummer kanting?

Why? He would agree that the kinetic energy of the falling disk is not being taken into account.

Would it not be 36.25 J? Assuming no heat or sound is generated...

That's a fake answer if it is right, since the two disks have non-rotational energy relative to one another, too.

Edit: it's...

Also, don't think I'm trying to insult you or call you names; I'm just a bit flamboyant in my metaphors, that's all.

No, you have the wrong answer. If you said "pretend that people and the cart are point-masses 13 m from the center of the circle," you'd have the answer, but the effective radius of the cart and...

My answer is zero.

There's not enough information to do the problem. We need to know where is the center of mass of the cart-person system, relative to the point at which the metal arm connects to the cart. We also...

That equation comes from adding the time from liftoff to firing the bullet (t1), to the time it takes the sound to reach the ground (the distance the helicopter's traveled divided by 320 m/s).

2 dimensions? This is a one dimensional problem. What's 'x'? I can't understand what you're doing. But I guess you do...

The way I did it was to solve

t1 + (3 m/s/s) / 2 * t1^2 / (320 m/s)...

80 m/s.

Equating PE + KE per kilogram at the faucet and half a meter below, we have

g * (0.5 m) + 1/2 * (2 m/s)^2 = 1/2 * v^2,

where v is the speed of the water at that point below. Then

v = sqrt(...

Okay, so, from now on let's assume that g = 10 unless stated otherwise.

Here's a problem:

A faucet is turned on; its spout faces straight downwards. It has radius 0.5 cm, and a 0.5 cm radius...

Okay, my answer 24.9 N is still correct; you assumed that g = 10 m/s^2; I assumed 9.80665 m/s^2.

Okay, now I'd really like to see the answer.

Oh, I see the problem. How about 10/7 * 1.5 kg * g + 0.4 kg * g, i.e. 24.9 N.

If so, then how about 12/7*1.5 kg * g, i.e. 25.2 N.

Wait, you want all the blocks to be moving differently so that _no_ two can be the same?

Near? Then my answer's wrong.

If relative to each other, then 2.4 kg * g, or about 23.5 newtons on Earth.

Relative motion? Relative to what? If relative to the surface, then there is no minimum (0 is the lower bound).

No, you do not know the maximum kinetic energy was lost from the fact that kinetic energy is not conserved in inelastic collisions; you know that the maximum possible amount of kinetic energy was...

No, you're right Infarction.

Your explanation does not use the principle of conservation of energy.

The purpose of this posting game is the following: Come up with an explanation of why posting games suck. The person with the most replies to this posting game thread is the loser. I'll go first....