isxrc> PLS PLS PLS can someone help. I have 24 hours from now and the clock is ticking.
The urgency is on your part, not on ours. You have chosen to fail already.
Read the rules of the forum. We do...

stat might give you what you want.

Drop the use of grep in this case, since it is not necessary.
sed 's/OUT.*$/IN/g' < original_file > result_file

If you want to continue using awk as the workhorse, then:
ls -l f3.sh | awk '{ if( NF > 7 ) { split($7, a, ":"); print a[1] } }'

As you have been shown you can pipe the ls command to another program that further parses the output, in this case awk.
awk can do a lot of things, but even in its simplest form it can be very...

Look into the command touch

if ( ${cnt} -ge "1" ) That reads if cnt is greater or equal to 1 therefore != would have not worked.

if ($cnt >= 1) then
# whatever you want to mail
endif

csh doesn't use if/fi but rather if/endif. Look at posted script and you'll see you have an if/fi.
BTW csh doesn't have the same conditional operators than bash so -ge doesn't work.

Post your code the way you wrote it to execute. Make sure there's a space between [ and ]

Find any difference between both and then match it. e.g. with HOOK by itself in a line we can match the beginning and end of the line. Thus:
grep '^HOOK$' file_name
Once you have down the...

It makes a difference the quotation scheme.
sed "/$npname.*in/d" parts.txt > parts.tmp

What's the trouble?
In its simplest form, create another executable script with three lines of text, where each line is the absolute path to those three scripts.

Your logic for including the matching pattern escapes me, however I can explain it to you.
This '$1 ~/^#/' tells awk to search for any line that in the first field the beginning of the line starts...

sed -e "s/$old_string/$new_string/" file1.txt > file2.txt

blackrobe> Can you please give me an example on how to use the "sed" command in this case??...

I can do better than that, I will give you a link to an easy to understand tutorial...

Arguments are parameters you pass to functions. Or referring to the command line is what you enter in the shell.
Assuming you have a script that needs two arguments when you run it at the command...

I am afraid that command doesn't produce the advertised result.

>Anyway, one more favor, care to explain
It would require a base understanding that would take some time to write. Fortunately, others has done it already. Take a look at this link...

Maybe (http://www.linuxquestions.org/questions/programming-9/bash-programming-create-a-menu-307345/)?

Continue to troubleshoot it, manually first, before creating a batch file.
In the current directory make a file that contain the y character alone.
In the current directory create another...

>the code is running but it i not deleting files.
I'm skeptic that this script runs properly. To start kiran.txt is in the same current directory that you are trying to delete *everything*.
And...

>But, I'll still look for that [one-liner].
Because originally you used the switch -i I assumed your version of sed was GNU.
Thus sed -ie "0,/$JOBNAMES/{//d;}" filename should have work.
However,...

Instead of :
sed -ie "\|^$JOBNAME\$|d"

try:
sed -ie "0,/$JOBNAMES/{//d;}" filename

The workhorse bit is "0,/RE/". It looks from starting line until first occurrence of REGEX

>I really am...

Your script doesn't make any sense, however I am going to guess some.
If you want to itinerate through the array ids you are missing something
for ((i=0;i<${#ids[@]};i++)); do



That...

>I wrote the solution in awk using substr() :


A slightly different approach. Since the targets to compare are found always in the beginning, use only the first field. Separate individual...

>any ideas?
I am not running any version of Solaris so I don't know what's the "gotcha."
But if sprintf() is doing the job after the suffix "GB" is erased, let's do it.
Make an awk file that...

>So sprint if getting the values however they still have either MB or GB on the end so therefore the sprintf statement wouldnt work would it?

Yes, it would. sprintf() tries to read and convert any...

>Why the variable $number is losing its value outside while loop
even though it's a global value?

It has to do with the pipe

Read here...

You get that result because sprintf is not receiving any value in column $2 that can convert into a decimal.
For debugging purposes substitute every line with a sprintf() call for just a print of $2...

Assuming data format:


For example purposes coming from datafile to awk and displaying to standard output. Modify to need.

awk '/s/ {
if ( index($2, "GB") ) {
$2 =...

Try this and see if you can figure out:

echo "2.3 4.56789" | awk '{printf "%.2f %.2f\n", $1, $2}'

>What does the e+11 and e+10 mean??
Search for scientific notation. When a number is large in length (very big or very small), a method has been invented to represent it using exponent.

>Basically, I want to know why the second script returns the line:
>Total size of files containing foo is: 0

Variable scope (http://www.nucleardonkey.net/blog/2007/08/variable_scope_in_bash.html)...

John, Manager, Finance, $2000
Jack, Accountant, Finance, $1500

If you take off the $ sign from the field value it might work.

[Edit] Don't disregard Salem's advice. You're lucky I didn't...

result=$(echo $var1 $var2 | awk '{print $1 - $2}')
$1 inside awk becomes whatever variable you past first, and $2 becomes the second variable and so on.
More about awk...

>That gives me the following error
Yeap, expr doesn't support floating points
In bash you'll need to use bc, calc, awk, or perl
But ksh-93 supports floating points
result=$(((($obyte2 - $obyte1)...

Variables in the shell are strings. Another utility is necessary to make the evaluation.
expr can do it, but has many "gotchas" that you need to be aware of, e.i. spaces, (), *, which need to be...

Whenever you log-in or open a new terminal window that starts the shell to run, a series of scripts are executed to establish the environment in which it is to run. These scripts contains commands...

Segmented, so you can understand better.
The first ^ says match beginning of a line.
The [^=] says match any character that is not a = sign. (the ^ inside [] is different that the one for the...

echo $1 | sed -e "s/^[^=]*=\(.*\)$/\1/"
echo $1 is the argument from the shell piped to sed but it doesn't have any thing to do with \1


What's \1? The first group remembered from the original...