@Deepak
Do not give away the solution. Read the last point of this link http://www.daniweb.com/forums/thread78223.html

Also posting C code in C++ forum is not a good idea that too without code...

Typecasting worked for me

if(i % 2 == 0) s -= 1/(float)(i*i);
else s += 1/(float)(i*i);

>>but howcome my version didnt classify as recursion when it did indeed call the function inside itself?

I didn't think it did because it does not fall into the conventional definition of...

I dont think your code classifies as recursion. Neither does it satisfy the question


This is what I would do to check if a link list is sorted using recursion

bool sorted(node *curr)
{
...

@ Ancient Dragon, the recursive function is incorrect. foo(x) has to return int. The correct version would be


int foo(int x)
{
if(x < 10)
{
x = x + 1;
return foo(x);
...

You have declared variables x,y,z as members of the class and also as parameter values of the function arith_ex
do something like this

void Calculator::arith_ex(int x,int y,int z)
{
...

For two matrices to be equal, the dimensions of both matrices have to be equal and the corresponding values should also be equal. I would follow niek_e's method to compare two matrices.

Insert line 20 inside the while loop and add the statement prev=prev->link; at the end of the loop.

For Q14

The else is binded to the second if statement, but note that the second if itself will be executed only if the first 'if' holds true. Its like saying
if(condition)
{
if(condition)
...

Lets take Q3, you have to know that void means that the function does not return any value. That means that option C is incorrect and A is perfectly valid. Option B is where one might get stuck, but...

An alternative could be using link list if you want to do it without STL. That way your first issue would be solved, but still the best way would be using vectors.

What is there you cannot understand? If you expect someone to hand out the answers then you are wrong.

You have created Node<K> *root; before defining the class Node. Declare it after the class. Furthermore I dont think you can use Node<K> n; outside the class. You will have to specify a valid class...

No you cannot. But you can pass the variables by reference so that the changes are reflected in the original variables. For example

void test(int &a,int &b)
{
a=a+1;
b=b+1;
}

int...

First of all please keep in mind to post your code using the code tags (http://www.daniweb.com/forums/announcement8-3.html). You have not done so even after Lerner told you.


total = total +...

The original is VB.

No I cannot. Do your own work yourself. Your last post is a lame attempt to make others do your work. Also read this http://www.catb.org/~esr/faqs/smart-questions.html
(Hope Salem dosn't mind me...

Please use code tags (http://www.daniweb.com/forums/announcement8-3.html) to post your code in future. A lot of energy of mods is spent on telling others to do the same it is the least you can do if...

You are not using your head and instead simply copy pasting the code. If you had read any of the posts above the mistake in my code would have been clear to you.

One way to about it would be to enter randomly either a 'X' or an 'O' at every turn of the computer. But this solution would not be very smart.

Another method could be exhausting all the possible...

number1 = number % 10;
number=number/10;
number2 = number % 10;
number=number/10;
number3 = number % 10;

No you are not. The base of the numbers is 10 not 100 or 1000. And you have used cout the wrong way


cout << endl << number<< number2<<number3;

A hint, divide a number by 10. The quotient would be the number except for the least significant digit and the remainder would be the least significant digit. Use these two in combination to get your...

Here are a few errors I can see

int List::sumOfNodes();

remove the ';' at the end.


while( currentPtr ! = null)

People here are not psychic. Kindly explaing what problem are you having with the code.

I am not sure, it has worked for me and I have never bothered to search. I will leave it for more experienced programmers to answer your question.

There is no need to use floor() as int truncates any decimal place as it is.

for any 4 digit number this should do the trick to extract all 4 digits

i=0;
while(number>0)
{
a[i]=number%10;...

Its not

cin >> number,first,second,third,fourth;


but

cin >> number>>first>>second>>third>>fourth;

Line 24, it just default, not case default


default:
cout << endl << "INVALID SELECTION!";
break;


And you cannot declare variables starting with numeral. Try this

I dont mind being called a geek because that is more or less what I am :)

Note that the '==' operator does not apply to float. You would get the output as C++ if you tried

if(f==.7)

For a client server model, you will have to code seperately for the server and seperately for the client. The server will basically keep track of all the data like scores, players etc. And the...

Okay one way to go about this would be using getline() (http://www.cplusplus.com/reference/iostream/istream/getline.html) to get the entire line. Use any delimiter to split the line into three...

The formula can be generalized as

index= ((row_num-1)*3) + (col_num-1)

where index is the index in the array
row_num is the row number of the element you want to refer and
col_num is the...

for(int i=countDown;i>=0;i-- )

mover is a pointer to wheel_node and contents is an int You cannot equate them as you have done in Line 6.

In order to create the link list you have to allocate memory using the new operator to...

No one here is going to code anything for you. You are better off with learning C++ and start coding on your own. The worst part of all this is that you expect people to do all the research and then...

Why cant you do it yourself?

Number of colums in the first matrix have to be equal to the number of rows in the second one. If you have only a row or a column matrix i.e. two arrays, their lengths have to be equal in order for...

@majestic0110
Random numbers come after applying the formula, it is however only to fool the end user :D. Lets say for example that I get result as '5' after application of the formula. Now I can...

That depends on how you want the love percentage to be calculated and if you want it to be the same for a given set of names. For example you can say that the love percentage will be higher if the...