Forum: PHP 4 Hours Ago |
| Replies: 2 Views: 138 I have tried php pagination, it only partially worked, giving me this message:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in... |
Forum: PHP 1 Day Ago |
| Replies: 2 Views: 138 This is my code:
<?php
//connect to mysql
//change user and password to your mySQL name and password
mysql_connect("localhost","root","PASSWORDREMOVED");
//select which database you want... |
Forum: PHP 2 Days Ago |
| Replies: 3 Views: 222 How would I use this in conjunction with my database records?
Also:
Also, how in SQL, automatically deleting the record after a certain time (e.g. in this case, the programme is an hour long,... |
Forum: PHP 3 Days Ago |
| Replies: 4 Views: 171 This is an included file on one of my PHP sites on localhost:
<?
//connect to mysql
//change user and password to your mySQL name and password... |
Forum: PHP 3 Days Ago |
| Replies: 3 Views: 222 I have tried again to solve this, but no luck so far... |
Forum: PHP 3 Days Ago |
| Replies: 4 Views: 227 I got another error, the error being this:
.
Here's my code:
<?php
//connect to mysql
//change user and password to your mySQL name and password... |
Forum: PHP 4 Days Ago |
| Replies: 4 Views: 227 I get these errors in a script of mine:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in C:\www\vhosts\myradiostation\test.php on line 13
and my original... |
Forum: PHP 4 Days Ago |
| Replies: 3 Views: 222 This is the code for my TV guide website (stored on localhost)'s articles in PHP:
<?php
//connect to mysql
//change user and password to your mySQL name and password... |
Forum: PHP 6 Days Ago |
| Replies: 6 Views: 232 I'm now getting this error:
I tried your code and got the above error... |
Forum: PHP 6 Days Ago |
| Replies: 6 Views: 232 I've been trying to create a database-driven site, am new to this, have looked it up on Google and tried for myself, but need a bit of help.
<?php
// Connects to your Database... |
Forum: PHP 22 Days Ago |
| Replies: 8 Views: 363 I was trying to set a HTML table with content already in place as an array - but if that's not possible, then not to worry, I will see what other HTML in arrays I can learn. |
Forum: PHP 23 Days Ago |
| Replies: 8 Views: 363 How do you get this to work? - well, for more than simple <strong> and <i> tags - I'm trying to get a HTML table in as an array, if this is possible!
Any advice is appreciated! |
Forum: PHP 29 Days Ago |
| Replies: 1 Views: 312 I've just been learning arrays, and so far it's going well :)
This is my current PHP code:
<?php
$states = array ('MD' => 'Maryland', 'IL' => 'Illinois', 'MI' => 'Michigan');
... |
Forum: PHP Nov 9th, 2009 |
| Replies: 11 Views: 379 Thank you for that advice - useful for if my site does have MySQL capacity, but my current webhost only offers PHP 5.28, with no databases available on the free hosting plan, so I've had to resort to... |
Forum: PHP Nov 9th, 2009 |
| Replies: 11 Views: 379 It is an episode guide for TV programmes, with the data stored in php variables. |
Forum: PHP Nov 9th, 2009 |
| Replies: 11 Views: 379 This is the variable for the episode titles:
$phptitle = "<NAME OF PROGRAMME>";
However, I have to manually change it for every page and add it as:
<?php
$phptitle = "test";
?> |
Forum: PHP Nov 9th, 2009 |
| Replies: 11 Views: 379 Do arrays have to be numbered automatically, or can they be like array[pagetitlename.php]? |
Forum: PHP Nov 3rd, 2009 |
| Replies: 7 Views: 315 I tried atli's suggestion, and it partly worked.
As for the URLs not being able to be found, they're only accessible locally, mapped via virtualhosts in Apache and a HOSTS file - otherwise... |
Forum: PHP Nov 3rd, 2009 |
| Replies: 7 Views: 315 Your code almost worked... except it displayed the same page repeatedly, despite the contents of 1, 2, 3, 4, 5, 6 and 7.php all being different.
How would I fix this? This code is for my localhost... |
Forum: PHP Nov 2nd, 2009 |
| Replies: 7 Views: 315 Basically what I'm trying to do... get the script to display a different page every day of the week. |
Forum: PHP Nov 2nd, 2009 |
| Replies: 7 Views: 315 This is my code which is intended to produce an URL like the following:
www.mysite.com/test.php?day=1
<?
if (!$_GET['day']) {
$day = date('N');
}
elseif ($_GET['day']==1){ ?>
<?php... |
Forum: PHP Oct 31st, 2009 |
| Replies: 11 Views: 676 $vwpassat = "<strong>\"<a href='$url1/buyers-guide/2010/volkswagen/passat.php'>VW PASSAT ARGENTINA</a>\"</strong>";
This seems to work - is this the correct syntax for bold quotation marks now? |
Forum: PHP Oct 31st, 2009 |
| Replies: 11 Views: 676 Thanks, that worked, however, how do I make the quotation marks bold within $autoguide1 - I only get the first one and it ends up as this:
- the second quotation marks set doesn't appear, for... |
Forum: PHP Oct 31st, 2009 |
| Replies: 11 Views: 676 Thank you for that - the code below worked:
However, what should I do to make the quotation marks bold within $autoguide1 without getting this error: |
Forum: PHP Oct 31st, 2009 |
| Replies: 11 Views: 676 This is the echo code from my site:
<?php
$url1 = "http://www.canadiandriver.com";
$url2 = "http://www.chevrolet.com.br";
$autoguide = "Autoweekly";
$autoguide1 = /"<b>"<a... |
Forum: PHP Oct 29th, 2009 |
| Replies: 11 Views: 379 I'm trying to set dynamic titles on my pages with a switch statement, but can't get it to work.
Tried ifelse using code gleaned from Google but it didn't work.
I'm trying to get it so that all... |
Forum: PHP Oct 29th, 2009 |
| Replies: 5 Views: 291 Now I'm getting this error message:
My code now:
<html>
<body>
<html>
<body>
<? |
Forum: PHP Oct 29th, 2009 |
| Replies: 5 Views: 291 I get this error now in my code:
Parse error: syntax error, unexpected '}', expecting T_ENDSWITCH or T_CASE or T_DEFAULT in C:\www\vhosts\mywebsite1\dayweek.php on line 25
<html>
<body>
<?
$i... |
Forum: PHP Oct 29th, 2009 |
| Replies: 5 Views: 291 This is my script, which is intended to show a different page depending on day of the week.
<html>
<? error_reporting(E_ALL);?>
<body>
<?
$i=$_GET['day'];
switch ($i) {
case 0: |
Forum: PHP Oct 27th, 2009 |
| Replies: 4 Views: 248 This is my code - which displays different articles and produces articles as http://www.mysite.com/testpage.php?test=1
<html>
<body>
<?
$i=$_GET['day'];
switch ($i) {
case 1:
... |
Forum: PHP Aug 24th, 2009 |
| Replies: 1 Views: 239 I've been trying out arrays recently, and this is my coding:
<?php
$data = array('autoguide1'=>'car',
'baz'=>'boom',
'scotland'=>'haggis',
... |
Forum: PHP Aug 22nd, 2009 |
| Replies: 0 Views: 194 I got arrays working first time! :)
This is the website's source code, the file is testing.php.
Source code:
<?php
$data = array('test'=>'testingpage',
'test1'=>'test1a',
... |
Forum: PHP Aug 7th, 2009 |
| Replies: 1 Views: 396 I'm trying to get multiple variables to work in the query string with PHP.
This is my code:
<?
$programme=$_GET['programme'];
switch ($programme) {
case 12578:
... |
Forum: PHP Aug 1st, 2009 |
| Replies: 6 Views: 638 What would I have to do to my query string?:
<?
$i=$_GET['carname'];
switch ($i) {
case 1:
include("1.php");
break;
case 2:
include("2.php"); |
Forum: PHP Jul 24th, 2009 |
| Replies: 6 Views: 638 I'm still trying to figure this out... anyone got any advice? |
Forum: PHP Jul 24th, 2009 |
| Replies: 6 Views: 638 Thanks for that. Do I have to create a separate .htaccess or php file to get this to work?
I have http://www.mychevycars.com (virtual host)
and I want to split the pages (page1.php, page2.php)... |
Forum: PHP Jul 24th, 2009 |
| Replies: 6 Views: 638 Thank you for the tutorial last time on query strings :)
It worked for me, this is my working query string:
<?
$i=$_GET['vehicle'];
switch ($i) {
case Chrysler:
include("chryslernew.php");... |
Forum: PHP Apr 11th, 2009 |
| Replies: 10 Views: 1,278 Thanks, rm_daniweb, that worked very well!
One question - how do I get it to automatically show the right page on the right day, e.g. it show's day 1's page on Monday etc. without people having to... |
Forum: PHP Apr 10th, 2009 |
| Replies: 10 Views: 1,278 Thanks for that. How would I use it with my code:
<html>
<body>
<? if($_GET['day']==1){ ?>
<?php include("day1.php") ?>
<? }else if($_GET['day']==2){ ?>
<?php include("day2.php") ?>
<?... |
Forum: PHP Apr 10th, 2009 |
| Replies: 1 Views: 396 I have a PHP page with query strings in, and that works, but getting it to display the correct page depending on the day via a switch statement is a problem.
This is the code:
<html>
<body>
... |