@VernonDozier: Yes, you're obviously right, I just wanted to make it as plain as possible for the OP :)

I hope this is not homework, so I'll show you a little more (it's simpler than it seems!) #include <iostream>
#include <string>
using namespace std;

int char2int(char c) {
switch(c) {
...

You could use atoi (http://www.cplusplus.com/reference/clibrary/cstdlib/atoi.html) or write your own char-to-digit converter, like this: int char2int(char c) {
switch(c) {
case '0':...

If a function returns, say, an int, you can use a call to that function in every place you could have used an int.
Examples:
#include <iostream>

int sumFunction(int a, int b) {
return a +...

Astonishing ignorance.

Thanks for posting, I'm waiting to read Chapter 2

What prevents your program from compiling is the following:

1) close doesn't need arguments - change both a.close("phonedir"); with a.close();.
2) else "" ; doesn't make sense. Maybe you wanted...

Change a[i]= tmp; with a += tmp;.

getline(cin, line);
Shouldn't you take your line from the ifstream?

What daviddoria meant with the add function is that you are every time rewriting the file instead of just adding lines.
...

string myFile("rawDictionary2");
int totalWords= wordCount(myFile);
you are sending in a string, why do you want it to accept an ifstream?

Ok, here are some hints.

Problem #1:

1 - main must return an int, so write int main() instead of just main()
2 - try to give more meaningful names to your variables (i.e. km instead of a,...

no looping at all - just one multiplication needed.
what have you tried?

Well if it's multiplication it's trivial... but I don't see any purpose in mentioning logarithms. Waiting for others to express their opinion on the matter.

Only thing I'd like to add is: avoid...

First general advice: use code tags (here (http://www.daniweb.com/forums/misc-explaincode.html) is an explanation of how) when posting code.
Second general advice: a more descriptive thread title...

As long as you are decrementing y you should put y in your base cases checks, otherwise multiply(2, wathever); would result in *endless* recursion.

EDIT: Sorry, Salem beated me in speed.

Seriously, how much do you think we care? Moreover, I hardly think so. I'm pretty sure that you won't hold gratitude or appreciation soon after you'll hand that assignment. Not that I'd pay a penny...

You have extra parentheses: write this if(strcmp(a,b) > 0) && (strcmp(a,c) > 0)

like thisif(strcmp(a,b) > 0 && strcmp(a,c) > 0)

If you are making a complex class you should return a complex object, and it should not be the first operand. I mean given z and w two complex number, the instruction z + w should not modify z!...

strange, #include <iostream>

using std::cout;
using std::endl;

int main(void) {
char * word = new char [20];
char temporal[ ] = "hola";
strcpy(word, temporal);
cout << word << endl;

Read this (http://www.daniweb.com/forums/post9554.html).

I'm fairly new to C++ in general and inheritance in particular so please someone correct me if I'm wrong: it seems to me like your methods definitions are conflicting with base class definitions of...

return ceil(sqft/115.)*cpg; here's your total paint cost. Divide by cost per gallon and you will obtain the number of gallons used Oo (read: do not multiply for cpg).

It's the same for the number...

val = true sets the content of val to true.

val==true checks the content of value.

They are two very different things! In your while loop and in the two if statements you need the second, so...

I'd do it that way too, just I'd add a little if-else-abs() trick to handle n<0 (otherwise it would print -567 reversed as -7-6-5).

something like if(n<0) {
cout << "-" << abs(n%10);
...

if(Number%2==0) {
cout << Number << " is even" << endl;
}
else {
cout << Number << " is odd" << endl;
}

Number % 2 returns the rest of the division by 2 (it's called modulus). ...