Search Results

Showing results 1 to 40 of 93
Search took 0.01 seconds.
Search: Posts Made By: campkev ; Forum: MS SQL and child forums
Forum: MS SQL Nov 19th, 2008
Replies: 6
Views: 2,619
Posted By campkev
While I don't want to discourage new members, you might want to look at the dates of previous messages. This thread has been dead for 2 and a half years.
Forum: MS SQL May 9th, 2008
Replies: 3
Views: 8,123
Posted By campkev
ignore that last one and try this instead


Select pt.ProductID
from Products pt
left join Rating RT
on pt.productid = rt.productid
group by pt.productid
order by IsNull(Min(rt.Rating),0)
Forum: MS SQL May 9th, 2008
Replies: 3
Views: 8,123
Posted By campkev
I think you want something like this

Select distinct pt.ProductID
from Products pt
left join Rating RT
on pt.productid = rt.productid
order by IsNull(Min(rt.Rating),0)
Forum: MS SQL May 9th, 2008
Replies: 1
Views: 1,401
Posted By campkev
get rid of the square brackets around the varchar(255) and it will work fine.

For that matter, why are you putting them around the datatypes anyway? I've never seen anyone do that.
Forum: MS SQL May 9th, 2008
Replies: 3
Views: 3,883
Posted By campkev
select * from persons where (prefix like '%'+@input+'%'
or
firstname like '%'+@input+'%'
or
lastname like '%'+@input+'%')
and address like '%'+@addressinput+'%'
Forum: MS SQL May 9th, 2008
Replies: 1
Views: 3,892
Posted By campkev
This isn't a problem as I have already solved the problem, just trying to figure out why it happened.

Ok I have a field that is type money. I wrote a stored procedure that updates this field,...
Forum: MS SQL Jan 24th, 2008
Replies: 5
Views: 937
Posted By campkev
that would add the assumption that the names in b are the first letter of the names in a
Forum: MS SQL Jan 24th, 2008
Replies: 5
Views: 937
Posted By campkev
ok, i am assuming that you want a name for all id's. if a has an entry use that, otherwise use the name from b. also assuming that B has an entry for every id. if those assumptions are correct,...
Forum: MS SQL May 22nd, 2007
Replies: 5
Views: 1,245
Posted By campkev
I don't have time to test this, but i don't think that this will work. This won't show any id1's that don't have a matching id2 or any id2's that don't have a matching one
Forum: MS SQL May 21st, 2007
Replies: 5
Views: 1,245
Posted By campkev
select distinct case when id1<id2 then id1 else id2 end, case when id1<id2 then id2 else id1 end from tablename
Forum: MS SQL May 18th, 2007
Replies: 7
Views: 4,475
Posted By campkev
um, yes you can. I have Windows XP Pro with SQL Server 2000 installed on it.
Forum: MS SQL May 11th, 2007
Replies: 7
Views: 4,475
Posted By campkev
Forum: MS SQL May 9th, 2007
Replies: 2
Views: 1,142
Posted By campkev
I agree that storing images in your database is probably not the best way to do it. But it is possible. Look into BLOB's (binary large object)
Forum: MS SQL May 3rd, 2007
Replies: 1
Views: 1,234
Posted By campkev
it think this should work

select nick, max(energy.dateposted) from users
join energy
on energy.userid = user.id
group by nick
Forum: MS SQL Feb 23rd, 2007
Replies: 1
Views: 4,244
Posted By campkev
there's probably a more efficient way but this should work
select max(empsal) from employees where empno not in (select top 3 empno from employees order by empsal desc)
Forum: MS SQL Feb 9th, 2007
Replies: 3
Views: 3,673
Posted By campkev
only other way that you might make it faster is to split the tables by type

eg have a SudokuGameList table and a CrosswordGameList table, ditto for history

but I really think that, with the...
Forum: MS SQL Feb 9th, 2007
Replies: 3
Views: 3,673
Posted By campkev
sounds like a reasonable setup. Best bet is to make sure it is indexed properly
Forum: MS SQL Feb 6th, 2007
Replies: 5
Views: 2,126
Posted By campkev
give an example of what you are trying to do
Forum: MS SQL Jan 12th, 2007
Replies: 2
Views: 5,173
Posted By campkev
1) I am in the process of doing this right now and so far it has been relatively painless. There are some minor tweaks you may have to make, but it is pretty easy to convert. Two problems we have...
Forum: MS SQL Jan 11th, 2007
Replies: 3
Views: 7,033
Posted By campkev
you're quite welcome
Forum: MS SQL Jan 11th, 2007
Replies: 3
Views: 7,033
Posted By campkev
not 100% sure what you are going for, but hopefully one of these will either do it for you or get you going in the right direction


1. this will give you each person and their max
select...
Forum: MS SQL Jan 5th, 2007
Replies: 3
Views: 3,350
Posted By campkev
from a practical standpoint, I had this happen on a database with an int identity column. You will get an arithmetic overflow exception. Since we are purging and only keep 60-70 million rows at a...
Forum: MS SQL Dec 20th, 2006
Replies: 2
Views: 2,687
Posted By campkev
this seems more like a code problem than an sql problem. try posting in the appropriate forum for the language you are using. (vbscript?)
Forum: MS SQL Dec 20th, 2006
Replies: 3
Views: 4,138
Posted By campkev
you want to use dynamic sql

DECLARE @STA as char(50)
SET @STA = '''TT'', ''DD'''

exec ('SELECT * FROM ABC_TBL where ABC_Filed in ('+'@STA')')
Forum: MS SQL Dec 20th, 2006
Replies: 1
Views: 3,623
Posted By campkev
sp_who
or
sp_who2
Forum: MS SQL Oct 19th, 2006
Replies: 5
Views: 5,149
Posted By campkev
does this work for you?

SELECT RNO,PNAME,AGE
FROM TAB1
WHERE enroll_status in ('D','A','Q')
Forum: MS SQL Oct 10th, 2006
Replies: 5
Views: 5,149
Posted By campkev
post the queries for the 3 lists and I should be able to help you do one query to get the combined list
Forum: MS SQL Sep 12th, 2006
Replies: 2
Views: 1,911
Posted By campkev
actually, that one will only work if there is something in cat a

this will work better


select distinct main.id, a.name, b.name, c.name
from tablename main
left join tablename a on main.id...
Forum: MS SQL Sep 12th, 2006
Replies: 2
Views: 1,911
Posted By campkev
this is what you want


select a.id, a.name, b.name, c.name
from tablename a
left join tablename b on a.id = b.id and b.cat = 'b'
left join tablename c on a.id = c.id and c.cat = 'c'
where...
Forum: MS SQL Sep 12th, 2006
Replies: 3
Views: 4,788
Posted By campkev
the problem with you original query was precedence

what you need is

WHERE (CHKCANCEL = '0') AND (DITD IS NULL) AND( (CUSTOMERID = '52') OR
(CUSTOMERID = '62') OR
...
Forum: MS SQL Jul 21st, 2006
Replies: 5
Views: 18,665
Posted By campkev
correct. 4 bytes * 8 bits = 32 bits. hence it has a range from -2^31 to +2^31
Forum: MS SQL Jul 21st, 2006
Replies: 5
Views: 18,665
Posted By campkev
you are confused, int is not limited to less than 10,000 in sql server. the limit is around 2 billion. (2^31)-1 to be precise
Forum: MS SQL Jul 10th, 2006
Replies: 1
Views: 1,408
Posted By campkev
well for stored procedures, just right click on them and click properties
for the triggers, right click on the table, then go to all-tasks and click on manage triggers
Forum: MS SQL Jul 7th, 2006
Replies: 7
Views: 11,597
Posted By campkev
are they stored in the time column, or their own column
Forum: MS SQL Jul 6th, 2006
Replies: 7
Views: 11,597
Posted By campkev
also, do you need minutes?
Forum: MS SQL Jul 6th, 2006
Replies: 7
Views: 11,597
Posted By campkev
and I suppose changing the database is out of the question?
Forum: MS SQL Jul 5th, 2006
Replies: 7
Views: 11,597
Posted By campkev
ok, let's start from scratch. give me a brief description of what exactly you are trying to accomplish. including field types and names

something like
I have three columns: workerid, begin_time...
Forum: MS SQL Jun 6th, 2006
Replies: 5
Views: 1,734
Posted By campkev
the way you want to do it, I don't know of a way without knowing the criteria you are sorting by and the table schema.

if you have a primary key and are sorting by that primary key,
example table...
Forum: MS SQL Jun 5th, 2006
Replies: 5
Views: 1,734
Posted By campkev
sorry, couldn't resist. Will need table schema to answer your question
Forum: MS SQL Jun 5th, 2006
Replies: 5
Views: 1,734
Posted By campkev
Showing results 1 to 40 of 93

 


About Us | Contact Us | Advertise | DaniWeb | Acceptable Use Policy | RSS Feed

©2003 - 2009 DaniWeb® LLC