Forum: Shell Scripting  Apr 14th, 2008 |
| Replies: 3 Views: 1,318 don't use useless cat with while loop
while read -r line
do
#processing
done < "file"
'
anyway, here's another way to solve your problem |
| Forum: Shell Scripting Mar 26th, 2008 |
| Replies: 9 Views: 2,346 no need to use cat
uuencode $file $file | /usr/bin/mailx -s "TEST" |
| Forum: Shell Scripting Mar 7th, 2008 |
| Replies: 8 Views: 2,562 awk 'BEGIN{FS="[]].[[]|[[]|[]]"}
{
gsub(/id|\"/,"",$13)
split($3,a,"/")
gsub("tag","",$16)
print $13,a[1],$7,$16
}' file |
| Forum: Shell Scripting Jan 15th, 2008 |
| Replies: 3 Views: 11,793 # echo $HTML | sed 's/<html><body>\(.*\)<\/body><\/html>/\1/'
OK |
| Forum: Python Sep 25th, 2007 |
| Replies: 4 Views: 3,064 it would be better to show a sample input file, your expected output as well.
to search in a file. just an example...considering i don't know what your file structure is like.
for line in... |
| Forum: Python Jun 14th, 2007 |
| Replies: 5 Views: 2,715 another way
>>> for i in range(len(sentence.split()),0,-1):
... print sentence.split()[i-1], |
| Forum: Shell Scripting May 13th, 2007 |
| Replies: 9 Views: 6,400 yes, you can put those into a script. use loops to create a counter for your files.
eg psedocode
count=1
awk '{print NR SEP $0}' SEP="/ " exfile1.txt
for counter in the range 1 to the number... |
| Forum: Shell Scripting May 13th, 2007 |
| Replies: 9 Views: 6,400 you can invoke the awk script again, or just use cp,
like: cp try2.txt <newfilename> |
| Forum: Python May 8th, 2007 |
| Replies: 7 Views: 1,262 Personally, i would use a loop for this.
num = 32
b1 = 10
b2 = 2
x = 1
while 1:
if num%(b2**x) < num:
x = x + 1
continue |
| Forum: Python Mar 29th, 2007 |
| Replies: 7 Views: 7,341 it's up to you. however its good to modularize so main() is definitely good to have. |
| Forum: Python Mar 29th, 2007 |
| Replies: 7 Views: 7,341 you can use splitext from os module
import os,shutil
def renamer(target) :
os.chdir(target)
for filename in os.listdir('.') :
print filename
newfilename =... |
| Forum: Python Feb 28th, 2007 |
| Replies: 4 Views: 1,763 For your particular example, you can convert your list to a string, then find 'a'
>>> a = [(' ', ' ', [('a', 'Scott'), ('9', 'vth')]), (' ', ' ', [('a', 'Jenny'), ('9', 'vth')])]
>>> b = str(a)... |
| Forum: Python Feb 21st, 2007 |
| Replies: 3 Views: 3,655 there are some cookbook recipe in ASPN you can refer to.
here (http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/82102).
they may not be wat you want, but at least will give you a head start |
| Forum: Python Feb 21st, 2007 |
| Replies: 2 Views: 1,197 you should read the docs more. also googling with "Python word count" will show you some links to what you are looking for. |
| Forum: Python Feb 19th, 2007 |
| Replies: 3 Views: 6,105 you can read in line by line
for line in open("file"):
if "word" in line:
do_something(line)
you can read in one whole chunk
data = open("file").read() |
| Forum: Python Feb 19th, 2007 |
| Replies: 5 Views: 15,946 there are several ways.
1) reading with for loop
o = open("output","a") #open for append
for line in open("file"):
line = line.replace("someword","newword")
o.write(line + "\n") ... |
| Forum: Python Jan 27th, 2007 |
| Replies: 5 Views: 3,015 Or you could do this
import operator
a = (1,2,3,4)
b = (4,3,2,1)
print sum(map(operator.mul,a,b)) |
| Forum: Python Jan 26th, 2007 |
| Replies: 8 Views: 3,604 Do you want to include decimals like 2.0 , 2.00000 etc as a whole number ?? |
| Forum: Python Jan 26th, 2007 |
| Replies: 9 Views: 4,177 Most string manipulation problems can be solved with Python's string functions. Only very complex ones will need regexp. So try not to use regexp if possible. Of course if you are good at it , then... |
| Forum: Python Jan 26th, 2007 |
| Replies: 8 Views: 3,604 you need to put a decimal before doing the division:
>>> 6.0/4
1.5
>>> 6/4.0
1.5
or you can import future: |
| Forum: Python Jan 26th, 2007 |
| Replies: 9 Views: 4,177 hi, wow, getter harder.:-)
anyway, here's a rather crude way and i am sure there are better ways (using re). I did substitution first, then do the rest
>>> data_raw = """
... header
... [23 ]... |
| Forum: Python Jan 25th, 2007 |
| Replies: 9 Views: 4,177 sorry somehow i can't find my edit button, but anyway
a decimal/float looks like this : 245.332 or 4.5 or 74.32
so to match them, we need one or more digits, followed by "." and followed by one or... |
| Forum: Python Jan 25th, 2007 |
| Replies: 9 Views: 4,177 another way is to use the "|" special character.
>>> re.findall(r'\d+\.\d+|\d+',data_raw)
['20', '35', '40', '84', '100', '245.99']
>>> |
| Forum: Python Jan 25th, 2007 |
| Replies: 15 Views: 2,528 i think its answered in the other thread |
| Forum: Python Jan 25th, 2007 |
| Replies: 15 Views: 2,528 hi there
sure, re.findall(r"(\d+)",data_raw)
thanks |
| Forum: Python Jan 24th, 2007 |
| Replies: 15 Views: 2,528 assuming data is as first posted:
>>> import re
>>> re.findall(r"\[(.*)\]",data_raw)
['20 ', ' 35 ', '40 ', '84 ', '100 ', ' 245', ' 260', ' 300 ', ' 440 ', ' 521 ', ' 650 ']
... |
| Forum: Python Jan 17th, 2007 |
| Replies: 6 Views: 1,900 can you try :
dates = [i for i in files for j in months if j in i ] |
| Forum: Python Jan 12th, 2007 |
| Replies: 7 Views: 7,138 another way...but you have to test it in different cases...
lst = [11, 'Dick', 12, 'Mary', 7, 'Zoe', 9, 700, 777, 'Paul', 13456789]
slist = sorted(lst) #sort the list
min_num , max_str =... |
| Forum: Python Jan 11th, 2007 |
| Replies: 6 Views: 2,098 what is your error, and what is your expected output/results? |
| Forum: Python Jan 9th, 2007 |
| Replies: 6 Views: 1,956 if you don't want to change list1, you can do
list1dup = list1[:]
list3 = add_item(list1dup)
... |
| Forum: Python Jan 9th, 2007 |
| Replies: 5 Views: 2,568 if you just want to find "Paul" in your example, one way to do it is to convert that list to string
astring = ','.join( str(i) for i in nested_list)
if "Paul in astring:
print "Found" |
| Forum: Python Jan 7th, 2007 |
| Replies: 2 Views: 1,010 this is the problem
grade = input("Enter gradepoint for course (Enter to quit): ")
input() expects a number. when you just press enter, it gives error
maybe a try:except can solve the... |
| Forum: Python Dec 29th, 2006 |
| Replies: 4 Views: 1,124 if your lists comparing only numbers, you can sort them first?
if sorted(li) == sorted(li2):
do something |
| Forum: Python Dec 5th, 2006 |
| Replies: 19 Views: 6,304 def en_de_code(text,flag=0):
if flag == 0:
return ''.join([chr(ord(char) + 1) for char in text ]) #encode
else:
return ''.join([chr(ord(char) - 1)... |
| Forum: Python Dec 2nd, 2006 |
| Replies: 8 Views: 5,850 In Python docs first para here http://www.python.org/doc/2.4.1/lib/typesmapping.html
"""
2.3.8 Mapping Types -- classdict
A mapping object maps immutable values to arbitrary objects. Mappings... |
| Forum: Python Dec 1st, 2006 |
| Replies: 2 Views: 13,250 do you want to comment out "import sys" and try again? |
| Forum: Python Dec 1st, 2006 |
| Replies: 4 Views: 2,484 >>> a = []
>>> if a:
... print "not empty"
...
>>> b = ['a']
>>> if b:
... print "not empty"
...
not empty
>>> |
| Forum: Python Oct 23rd, 2006 |
| Replies: 4 Views: 2,211 hmm.list comprehension?
alpha = [ c for c in list if str(c).isalpha()]
number = [ c for c in list if str(c).isdigit()]
if you want to get unique elements, use set |
| Forum: Python Oct 19th, 2006 |
| Replies: 3 Views: 1,966 if you look at the xrange() docs. it says "returns an ``xrange object'' instead of a list"
if you want to use xrange(). use a for loop
for i in xrange(1,5):..... |
| Forum: Python Sep 29th, 2006 |
| Replies: 4 Views: 1,088 it's best if you could explain what you wish to do, give sample input and output if possible |
