For example, suppose you have a function
int f(int n) {
if (n == 0) {
return 1;
}
else {
return n * f(n-1);
}
}
We want to measure its cost. But before we do so, we'll...

Create a recursive formula for the time complexity and figure it out from there.

Hey, you're right, it is easy for me.

Let's look at this one. I'm going to ignore the swap for now.
Iteration2:
public static long dominoes(long x, long y){
long temp;
double koeficient = 0, faktor;
for(long i=0; i<=x+y;...

Addition is O(n) where n is the number of bits in the BigInteger, and multiplication depends on the algorithm used: http://en.wikipedia.org/wiki/Multiplication_algorithm . That depends on the Java...

Search for it on Google. It's a nice language that has access to all the Java libraries.

Learn Clojure.

When you run a Theta(n) operation n times, it takes Theta(n^2) time to do. I mean in general if you run an operation that takes n seconds n times, it's going to take n*n seconds.

No, when n is the size of the array, resizing takes Theta(n) time because you have to copy all the elements.

You would just write that each push and pop wolud take Theta(n) time. (And so the average time per operation is Theta(n) which is bad because we'd like it to be O(1).)

MS Visual C++ Express. It should work.

Edit: as a stopgap, if you're short on time, you can run single-file C++ programs at http://codepad.org/ . But it's in your best interest to get a compiler...

You can compile and run the program if you want to see if it works.

Yes, read through the Time Complexity of Algorithm thread. It's a very old thread and has practical and theoretical answers.

What courses are available and which ones are good depends on which school you're going to. There is a lot of variety in the ways various computer science departments teach.

I'm going to haunt all your posts and make your existence on this forum a miserable one.

...

Anyway, your first example (where A gets assigned 54) is perfectly right.

When you store something in B, that means the predefined value will be overwritten.

Well clearly, the matrix manipulation class should provide clear error messages, throwing exceptions when you try to do impossible things. What do you expect integers to do when you divide by zero? ...

Define 'provider' and define 'consumer'. What do you mean by 'putting a car in a garage'? That analogy can mean different things. (Maybe just tell us what you're doing.)

No.

What is the purpose of this post?



Reality disagrees with you.

Nobody could help you unless you listed specific books for which you wanted solutions manuals. And since nobody here would know how to find them off the top of their heads, you might as well do the...

Why should I?

Use C#, not Java. Java is the worst language in popular use, besides C++.

And that doesn't matter. If you want better code writing techniques in languages like C#, the easiest and best way is to learn Haskell.

Yes.

Learn Scheme, C++, Haskell, and C#. That will take some time. You have to actually do projects in them, of course.

The languages you've listed, and most other languages, are not worth learning...

How much money? 2 hours = $400.

It's not that hard. First you can just grep the compiler name. For Haskell you can grep '.lhs'. If that fails, then for any compiled gc'd language you can just look at the garbage collector. ...

Um, it's hard to understand you, so I'm going to guess that the answer depends on the definition of 'driver'.

Edit: but more seriously, I'd say no, based on the way the word 'driver' is used in...

MinGW, not MiniGW.

Store the array alongside a 'multiplier value' that you multiply the elements of the array by when reading them (and divide by when writing...). Then have MultiplyAll simply change the multiplier...

That does the trick, except that computing A[j]/n takes log(n) time. But it is nice.

Because it's wrong. You can make assumptions of O(1) comparison for comparison-sort based algorithms, mainly because the comparison operation is in fact O(1) average over the course of the sorting...

Considering that computing sqrt(N) takes log(N) time (at least), square rooting all the integers that you're sorting will doom you to N*log(N) complexity. And it will just arrange your elements into...

Are you sure you don't need to provide O(N) _average_ time?

Here's some ideas about strategy: First of all, consider an extreme case, where sqrt(n) buckets have sqrt(n) elements fall into them. Well, know (by induction) that any bucket with more than...

What about something like this:

Make buckets for the ranges 0..n-1, n..2n-1, ..., n^2-n..n^2-1.

Then, first go through the array and fill the buckets with counts of how many elements fall in...

Now what do you mean, saying array insertion is carried out in constant time? What do you mean by insertion? Exactly what datastructure are you using to represent the array? If you've got some...