Your logic is wrong. 1 KM == 1000 M == 100000 CM.

You should really watch the Fast and the Furious, then you would have known: Nitrous Oxide Systems (http://www.holley.com/index.asp?division=NOS)

In that case, just make the change I suggested in my previous post and this problem should be solved!

What is 'String' ? What are you sending to this function; can you show how you call it? Because I suspect you want:
void update_rw_requests(ReadOrWrite rw, char* algorithm)

Yes! That's exactly what I meant! Good job.



I've asked to move this thread to the C-forum

Come on, look at the code closer:

for(i=0; i<N; i++)
{
printf("enter a number");
scanf( "%d", &nwr);
newary[i] = nwr;
}

Some people don't get your twisted way of thinking/humour and mistakenly think that your making fun of them. That's what you get with a forum full of geeks.

Off-topic: bowling sucks, big time. :)

for c:


/*code goes here */



also explained here (http://www.daniweb.com/forums/announcement8-3.html)

Telekinesis seldom works for me



How about I help you in the right direction and still stay a sarcastic kind of guy?

Here's a link ...

With a computer, keyboard, monitor, mouse (optional), an OS and some software. You'll probably need your eyes, brains, arm, hand etc too.

In other words: Try something yourself first and come back...

because 'i' is already an declared as an int. 'A' was declared as an array of doubles.

Now in your particular case i and a[i] have the same value because of the initializing for() loop you asked...

It initializes the array with the values 1-10.
It's a loop. Every time the loop loops, one element of the array will receive a value. So the first pass i == 0, so a[0] will become 0. The second...

A bit of-topic, but a moderator (WaltP) once wrote this (http://www.gidnetwork.com/b-59.html)article about scanf(), it's worth the read. (also click the other parts about scanf)

For the rest I...

Hmm. Let's ask:

@gargg321:

Do you want an array like this:
a[0] = 31
a[1] = 1
etc

or like this:

@AD:

But that's not what he wants right? I thought he wanted the decimal values of the hex numbers stored as a string in a char-array?
So my code should be OK

Change the %x to %d with the sprintf()
use %c when printing the chars

this code:

int main()
{
char a[25];
int i;
sprintf(a,"%d%d%d",0x0000001F,0x00000001,0x00271418);

I'm actually working with a program for a Fujitsu uController at the moment. Written by (with all respect) an old-school programmer. static this, extern that... bleh..
I'm more of a 'throw pointers...

Another thought comes to mind:
Where is your input.txt? Is it in the same folder as the executable? If not: crash

That's very strange... AD is right a getchar() should do the trick.
Try replacing the getchar() with:
while(getchar()!='q'){}

Now you'll have to enter a 'q' and 'enter' to quit

Two things:
This is a typo: FILE *ifp, ; Remove the comma: FILE *ifp ;

And you might want to read this about void main...

Actually, main DOES return a value. Never mind what you teacher told you or what Turbo thinks is normal, main returns an int. So use int main(void) and return 0;

If you are switching compilers,...

So I see...

Perhaps my brain misfired there for a second. Sorry bout that. But the link is still usefull (about pointers)

Click here (http://www.cplusplus.com/doc/tutorial/pointers.html)

Also: If you have a question, you should start your own thread (http://www.daniweb.com/forums/faq.php?faq=daniweb_policies), not...

That's what you get for using Turbo C ;)

Better option (IMO) are:
- visual studio express (http://www.microsoft.com/express/vc/)
- Bloodshed DevC (http://bloodshed-dev-c.en.softonic.com/)
-...

Close, but a few things:
- it's int main() and return 0; Click here (http://faq.cprogramming.com/cgi-bin/smartfaq.cgi?answer=1044841143&id=1043284376)for info
- Clrscr() is not standard. I'm using...

if you want the power of something, you need the pow() function. You can't do y^2, you need to write it like pow(y,2);

Niek

I've had this problem in the past. I used a custom function made by someone else, because I couldn't write my own...

Click...

Did you #include <windows.h> in your project?

If it only get's that error if the FIRST char = '?' or '*'try checking if 'err' == REG_BADRPT . If so: report back.

Niek

Haha :)

Perhaps you should add a getchar() before your return 0; , this keeps the window open when the program is done running.
The code you've posted works fine, I've tested it on VC8 with my...

It's allowed both ways by compilers, (because sizeof is an operator, not a function) but I always put brackets around the 'argument' for readability. It's a mather of personal taste, like indenting...

Minor correction on that one:
while ( fgets( str, sizeof(str), fp ) != NULL )

regards Niek

I tried to run your code and came across the above. You're checking if x<10 BEFORE it is assigned a value... This will crash your program.
Change it to this:

x=z%10;
if (x<10)

And you're...

What WaltP is trying to say is that: if (x<10&&x>20) is wrong:
This statement means: if x is less then 10 AND bigger then 20. What number do you know that is smaller then 10 and bigger then 20?...

I would also check if opening the file(s) was a succes or not. This will spare you the memory exceptions in the future.

Niek

Sure:
system("more /proc/cpuinfo > /tmp/file");
Now just open the file /tmp/file and read the data that you want.
Or you could use a named pipe with one end in your C-program and "more...

No such problem here. I have to agree with Narue, your code works (more or less) for me. There are a few other thing wrong with it though: Always initialize your vars with a value! Always check if...

That's because the char you entered is still in the buffer. It's a bug in scanf(), you shouldn't use it. Link (http://faq.cprogramming.com/cgi-bin/smartfaq.cgi?answer=1044873249&id=1043284392)
Also:...

Not quite there yet. Try 11 rows. The formatting will be all messed up because your program doesn't take into account that numbers might have more then 1 digit, so the more rows you enter, the more...

printf(" %5d",a[1][1]);
That's your first line, so that's the maximum number of spaces from the left of the screen. This won't work, because if you get more then 3 lines there won't...