Forum: C++ Oct 28th, 2008 |
| Replies: 8 Views: 944 ehh, now i'm confused... it would be helpful to see some code you've done already, but this is my suggestion: don't use a stack. it's a maze... a pretty straightforward graph. if you know where you... |
Forum: C++ Oct 10th, 2008 |
| Replies: 19 Views: 1,512 you can access them by memory addresses... so the integers should be given addresses that are consecutive. could count as pointing really. |
Forum: C++ Oct 6th, 2008 |
| Replies: 12 Views: 1,407 i still don't really get it... if the input is in shape of (ax+b)(cx+d) you can easily solve this to acx^2+x(ad+bc)+bd, which you can simply extract from your string looking at them as being just... |
Forum: C++ Oct 2nd, 2008 |
| Replies: 12 Views: 1,407 if you could post a more detailed description of the problem... if you're only working with square binomials it should be really simple.
for example, if the shape of the input is
ax^2 + bx + c,... |
Forum: C++ Aug 15th, 2008 |
| Replies: 13 Views: 2,704 i love scanf( "\n" ); :) i only use it to keep the program from stopping anyways, you can use system( "pause" ); for that and comment it out afterwards. i only use it cause i don't run my programs... |
Forum: C++ Aug 15th, 2008 |
| Replies: 13 Views: 2,704 hehehe, you have an "i++;" in your for loop...
so it actualy reads every second number.
if you remove it it will read all |
Forum: C++ Aug 15th, 2008 |
| Replies: 13 Views: 2,704 here...this should work...
#include <iostream>
using namespace std;
int number, sum = 0;
int main( void )
{
cout << "This program computes the average of 10 numbers" << endl; // you can... |
Forum: C++ Aug 15th, 2008 |
| Replies: 13 Views: 2,704 hmmm...lemme analyze this abit:
#include <iostream>
#include <cmath>
using namespace std;
const int MAX = 10 + 1; //let it have more space
//Main Module
int main() |
Forum: C++ Aug 8th, 2008 |
| Replies: 15 Views: 1,445 namespaces are generaly used to avoid conflicts that could happen if you have two functions, classes, etc. with a same name...
so if you've got a libraries "libA" and "libB"
and in each of those... |